Answer:
B
Step-by-step explanation:
This is how I am confirming the answer:
14/125 = 0.112
125(0.112) = 14
Let the number of type A surfboards to be ordered be x and the number of type B surfboards be y, then we have
Minimize: C = 272x + 136y
subject to: 29x + 17y ≥ 1210
x + y ≤ 50
x, y ≥ 1
From the graph of the constraints, we have that the corner points are:
(20, 30), (41.138, 1) and (49, 1)
Applying the corner poits to the objective function, we have
For (20, 30): C = 272(20) + 136(30) = 5440 + 4080 = $9,520
For (41.138, 1): C = 272(41.138) + 136 = 11189.54 + 136 = $11,325.54
For (49, 1): C = 272(49) + 136 = 13328 + 136 = $13,464
Therefore, for minimum cost, 20 type A surfboards and 30 type B surfboards should be ordered.
Answer:
If 32 students are enrolled in the course, there would be 24 girls.
Step-by-step explanation:
Given that For every boy in an advanced math course there are 3 girls who are taking the course.
It means if there are four students in the class. There would be 3 girls and 1 boy. Thus, 75% of the students are girls.
Given that there are 32 students enrolled in the course.
so
75% of 32 = 75/100 × 32
= 24
Thus, if 32 students are enrolled in the course, there would be 24 girls.
The number of solutions of a quadratic equation
ax^2+bx+c=0
Depends on its discriminant
/Delta=b^2-4ac
If /Delta>0 there are two distinct solutions
If /Delta=0 there are two coincident solutions
If /Delta<0 there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
The number of solutions of a quadratic equation
Depends on its discriminant
If there are two distinct solutions
If there are two coincident solutions
If there are no solutions.
We know that there are two real solutions (I assume you mean distinct solutions), so we know that the discriminant is positive:
b^2-4ac=9+28t>0\iff t>-\dfrac[9][28]
