We'll need to find the 1st and 2nd derivatives of F(x) to answer that question.
F '(x) = -4x^3 - 27x^2 - 48x - 16 You must set this = to 0 and solve for the
roots (which we call "critical values).
F "(x) = -12x^2 - 54x - 48
Now suppose you've found the 3 critical values. We use the 2nd derivative to determine which of these is associated with a max or min of the function F(x).
Just supposing that 4 were a critical value, we ask whether or not we have a max or min of F(x) there:
F "(x) = -12x^2 - 54x - 48 becomes F "(4) = -12(4)^2 - 54(4)
= -192 - 216
Because F "(4) is negative, the graph of the given
function opens down at x=4, and so we have a
relative max there. (Remember that "4" is only
an example, and that you must find all three
critical values and then test each one in F "(x).
Answers:
120kmh = 72.168mph
50kmh = 31.07mph
Explanation:
This is very simple, just multiply 120kmh by 0.6214 to get 72.168mph. Again multiply 50kmh by 0.6214 to get 31.07mph
Answer:
Assuming the asterisks are exponents, then OD and exponential equation has to have both a multiplier(exponent).
Step-by-step explanation:
For 37 you have a 90° angle, so you add 6x + 14 and 3x + 29 and get 9x + 43 and now set this equal to 90 and solve for x, and then plug x into the original equation for each angle to solve
