Answer:the last one
Step-by-step explanation:
Given differential equation, (D4 - 5D3 + 5D2 + 5D - 6)y = 0
=> For general solution of equation,
Solve D4 - 5D3 + 5D2 + 5D - 6 = 0
=> D4 - 5D3 + 6D2 - D2 + 5D - 6 = 0
=> D2 (D2 - 5D + 6) - (D2 - 5D + 6) = 0
=> (D2 - 5D + 6)(D2 - 1) = 0 ................................(1)
Now
D2 - 1 = (D - 1)(D + 1) and
Factors of D2 - 5D + 6
D2 - 5D + 6 = D2 - 2D - 3D + 6
= D(D - 2) - 3(D - 2)
= (D - 3)(D - 2)
Therefore, equation (1) implies
(D2 - 5D + 6)(D2 - 1) = (D - 3)(D - 2)(D - 1)(D + 1) = 0
=> D = 3, 2, 1, -1 or D = -1, 1,, 2, 3
=> General solution of differential equation is,<span>
=><span> y = C1 e-x + C2 ex + C3 e2x + C4 e3x</span> .
Hope it helps
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The answer is C) because you are moving left 8 units. In the inside of the parenthesis it says +8 however its counterintuitive, so the function is actually moving left. You can check on desmos.com a website for graphing functions.
Given :
On a number line, suppose the coordinate of A is 0, and AR = 15.
To Find :
the possible coordinates of the midpoint of AR.
Solution :
Their can be two points R which is at a distance of 15 units from the A .
One is -15 and other is 15.
Now, mid-point of A(0) and R(-15) is M (-7/2).
Also, mid-point of A(0) and R(15) is M (7/2).
Therefore, possible coordinates of the midpoint of AR is 7/2 , -7/2.
Hence, this is the required solution.
