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Ulleksa [173]
3 years ago
7

F(x)=-x^(4)-9x^(3)-24x^(2)-16x what is the relative maxium and minimum?

Mathematics
1 answer:
stepladder [879]3 years ago
7 0
We'll need to find the 1st and 2nd derivatives of F(x) to answer that question.

F '(x) = -4x^3 - 27x^2 - 48x - 16     You must set this = to 0 and solve for the 
                                                           roots (which we call "critical values).

F "(x) = -12x^2 - 54x - 48

Now suppose you've found the 3 critical values.  We use the 2nd derivative to determine which of these is associated with a max or min of the function F(x).

Just supposing that 4 were a critical value, we ask whether or not we have a max or min of F(x) there:   

F "(x) = -12x^2 - 54x - 48    becomes    F "(4) = -12(4)^2 - 54(4)
                                                                        =  -192 - 216
                                       Because F "(4) is negative, the graph of the given
                                        function opens down at x=4, and so we have a 
                                        relative max there.  (Remember that "4" is only
                                       an example, and that you must find all three
                                        critical values and then test each one in F "(x).
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You know its a square. Which means all the sides are equal and same length. If you dont know what's a square then here is the definition:

Square is a plane figure with four equal sides and four right (90°) angles.

So now we know both of are squares, in case of the first square, PQRS, one side length is already given which is PQ=9cm. Now one side is 9cm which means all the sides are 9cm's (PQ=9cm, QR=9cm, RS=9cm,SP=9cm). So to find area just multiply them:

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Now you found the area of the first square. So for the second square, ABCD, one side length is 5 cm so all the rest three sides are also 5 cm. Again, multiply them in order to find the area:

5cm * 5cm = 25cm^2

So square PQRS is 81cm^2 to that of square ABCD is 25cm^2

CAUTIONS: IT IS NOT THAT HARD YA KNOW

By the way, hope it helps! ^^

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