1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s2008m [1.1K]
3 years ago
12

Jeremy is 15 years old. His father is 4 times as old as him now. In how many years time will their total age be 115 years?

Mathematics
2 answers:
Anton [14]3 years ago
4 0
Fifty five is the answer!
brilliants [131]3 years ago
3 0

Answer: The answer is fifty five.

You might be interested in
HELP WITH ANY OR ALL THESE PROBLEMS ASAP PLEASE LIKE NOW PLEASE<br>CAN SOMEONE PLEASE HELP 
LiRa [457]

Ques 8:

The Volume(V) in cubic feet of an aquarium id modeled by the polynomial function V(x)= x^{3}+2x^{2}-13x+10

a) We have to explain that why x =4 is not a possible rational zero.

By Factor theorem, which states that a polynomial f(x) has a factor (x - k) if and only if f(k)=0.

For this , we will substitute the value of x in the given function.

V(x)=x^{3}+2x^{2}-13x+10

V(4)=4^{3}+2(4)^{2}-13(4)+10

V(4)=4^{3}+2(4)^{2}-13(4)+10

V(4)=54 which is not equal to zero.

Therefore, x=4 is not a possible rational zero.

(b) To show that (x-1) is a factor of V(x).

By Factor theorem, which states that a polynomial f(x) has a factor (x - k) if and only if f(k)=0.

Let (x-1)=0

So, x=1.

Substituting x=1 in the given function.

V(1)=1^{3}+2(1)^{2}-13(1)+10

V(1)= -10+10

V(1) = 0

Therefore, (x-1) is a factor of V(x).

Now we will factorize the given function.

Dividing the given function by (x-1).

On dividing, we get quotient as x^{2}+3x-10

So, factored form is = (x-1)(x^{2}+3x-10)

= (x-1)(x^{2}+5x-2x-10)

= (x-1)(x(x+5)-2(x+5))

=(x-1)(x+5)(x-2)

(c) So, the dimensions are 1,2 and -5.

5 0
3 years ago
Find the equation of a parabola with a vertical axis and its vertex at the origin and passing through the point (-2, 3)
vredina [299]

a vertical axis, I assume it means a vertical axis of symmetry, thus it'd be a vertical parabola, like the one in the picture below.

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \qquad \leftarrow vertical\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=0\\ k=0 \end{cases}\implies y=a(x-0)^2+0 \\\\\\ \textit{we also know that } \begin{cases} x=-2\\ y=3 \end{cases}\implies 3=a(-2-0)^2+0\implies 3=4a \\\\\\ \cfrac{3}{4}=a~\hspace{10em}y=\cfrac{3}{4}(x-0)^2+0\implies \boxed{y=\cfrac{3}{4}x^2}

8 0
3 years ago
A certain triangle has two 45° angles. What type of triangle is<br> it?
wariber [46]

Answer:

an acute triangle

Step-by-step explanation:

an acute triangle has angles that are less than 90 degrees

right triangles have a right angle

obtuse triangles have angles greater than 90 degrees

5 0
3 years ago
I have 4 sides that are the same length but no right angles
Marysya12 [62]

Answer:

Its a rhombus

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Which expression has the same value of x³ ?
kumpel [21]
The answer is C I am so sure
5 0
3 years ago
Other questions:
  • How many cups does it take to make a gallon of water
    11·1 answer
  • Can someone please help me thanks :)
    9·1 answer
  • Circle O and circle P are congruent. What can you conclude from the diagram?
    10·1 answer
  • What is the volume of the right prism?<br><br> ________ in3
    9·1 answer
  • Which logarithmic equation is equivalent to the exponential equation below?
    15·2 answers
  • Please help! will give 50 points
    12·2 answers
  • Mario paid $44.25 in taxi fare from the hotel to the airport. the cab charged $2.25 for the first mile plus $3.50 for each addit
    8·1 answer
  • (2^3)^2 (2^-2) / (2^2) (2^0)
    7·2 answers
  • HELP ME I NEED THIS RN
    10·1 answer
  • What is 3t – 6 = t –2.
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!