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Paladinen [302]
3 years ago
6

The Discriminant of a quadratic equation is -6. What types of solutions does the equation have?

Mathematics
2 answers:
erastovalidia [21]3 years ago
5 0

Answer:

2 complex conjugates

Step-by-step explanation:

The discriminate is the part of the quadratic formula that is under the radical sign.  If the discriminate is negative, that means that the solutions, both of them, are complex conjugates, aka imaginary solutions.

zalisa [80]3 years ago
4 0

For this case we have that by definition, the discriminant of an equation is given by:

D = b ^ 2-4 (a) (c)

We have the following cases:

D> 0: Two different real roots

D = 0:Two equal real roots

D Two different complex roots

In this case we have to:

D = -6, -6 , Then we have two different complex roots.

Answer:

OPTION B

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Write the numeral to represent four hundred and eight thousand and sixty-four
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408,064

Step-by-step explanation:

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An item is purchased for a wholesale price of $48 and will be sold at a 55 percent markup. Which expression should be used to fi
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A recently negotiated union contract allows workers in a shipping department 24 minutes for rest, 10 minutes for personal time,
Alik [6]

Answer:7.125 min

Step-by-step explanation:

Given

Resting time =24 min

Personal time=10 min

Delay=14 min

Observed Time=6min/cycle

Performance Rating=95%

Allowance Time=Rest time+Personal time+delay

Allowance time=24+10+14=48 min

Allowance %=\frac{Allowance Time}{Total Time}=\frac{48}{4\times 60}=20 \%

Allowance Factor=\frac{1}{1-0.20}=\frac{5}{4}

Calculate the Normal Time

Normal time=Observed time\timespersonal Time=6\times 0.95=5.7 min

Standard time=Normal time \times Allowance Factor

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3 0
3 years ago
Why is 3.14144144414444.... not ??
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Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
2 years ago
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