Answer:
5
Step-by-step explanation:
The problem is set up as 55/11.
55/11=5
Hope this helps!
Answer:
10-8x
Step-by-step explanation:
because it is 10 minus 8x
but 8x is 8 times x
plz brainliest :)
Answer:

Step-by-step explanation:
Given that the bag contains black and red marbles.
Number of black marbles in the bag = 2
Number of red marbles in the bag = 3
Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5
Let us have a look at the formula for probability of an event E, which can be observed as:


Now, the marble chosen at first is replaced.
Therefore, the count remains the same.

Now, the <em>required probability</em> can be found as:

Answer:

Step-by-step explanation:
Given


Required
The equation of the perpendicular bisector.
First, calculate the midpoint of the given endpoints



Open bracket


Next, determine the slope of the given endpoints.




Next, calculate the slope of the perpendicular bisector.
When two lines are perpendicular, the relationship between them is:

In this case:

So:


Since the slope is
, the equation is:

Where:

Recall that:

So:

Hence, the equation is:
