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max2010maxim [7]
2 years ago
14

how is the sentence “12 less than x is four” written as an equation? 12 – 4 – x = 0 x = 12 – 4 x – 4 = 12 x - 12 = 4

Mathematics
1 answer:
nordsb [41]2 years ago
7 0
This is saying that four is the result of a number "x" minus 12....therefore the equation is x-12=4
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Zoom in to see the question plzzz help!!!
kondor19780726 [428]

Answer:

\huge\boxed{\boxed{IV}}

Step-by-step explanation:

Given:

x>0

Which means

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y<0

Which means

y Is any number smaller than 0

ig -1,-2,-3,-4,-5.........

So according to the question

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Find the surface area of the pyramid. The side lengths of the base are equal.
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362.02

Step-by-step explanation:

8 0
2 years ago
Zero and negative exponentswrite in simplest for without zero or negative exponents- 17 ⁰
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4 0
11 months ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
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