Answer:
C
Step-by-step explanation:
There isnt infinite because there is an answer of 19, and only so many whole numbers can add up to 19
There isnt 1 because 11+8 and 5+14 both equal 19
Answer:
(7v +3 ) ( v + 4 )
Step-by-step explanation:
7v^2+31v+12
(7v + ) ( v + )
12 = 1*12
2*6
3*4
7* 4 + 3 = 31
(7v +3 ) ( v + 4 )
Answer:
1. (a-c)
+ b
2. 9m + 2
3. 6a
4. (5a - 3b)
Step-by-step explanation:
1. since a and c share the same squareroot x, you can combine these together.
2. First add like terms together. 4m - m + 6m = 9m. Then 5 and -3 combined equals 2
3. First simplify the square roots. squareroot of 16 is 4. square root of 49 is 7. square root of 81 is 9. They are all multiplied by a in the expression. Thus 4a - 7a + 9a = 6a
4. First simplify the radicals, they are not perfect. square root of 125 is equivalent to sqrt(25 * 5), which sqrt of 25 is 5, but we keep the sqrt of 5. For sqrt of 45, it is the same as sqrt9 * sqrt5. sqrt of 9 is the same as 3 and we keep sqrt 5. Thus we get the below:
5a - 3b
We can combine the two like terms and get the final answer above.
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The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
