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horrorfan [7]
2 years ago
12

An enrolling high school student has the following subjects to open to her:

Mathematics
2 answers:
adell [148]2 years ago
8 0
So we notice that they increase by 1
each time
first slot we have all of them so
4 choices=1st slot
3 choices=2nd slot (1 was taken for 1st slot)
2 choices
1 choice
multiply
4 times 3 times 2 times 1=24
answe ris 24 ways
 

ikadub [295]2 years ago
8 0

From the other answer, I see that my colleague with the busted clock
interpreted your question in a different way.  So I should explain
how I understand your question.

I understand you to say that both English sections meet at the
same time, all 3 math sections meet at the same time, all 3 History
sections meet at the same time, and all 4 Biology sections meet at
the same time.  So our student will take the subjects in that order,
but for each period, she can choose which section to join.
If that's not the right way to understand the question, then it's definitely
too complicated for me.

Reading it MY way,
here's the solution:

English: 2 choices.  For each of those . . .
Math:     3 choices.  For each of those . . .
History:  3 choices.  For each of those . . .
Biology:  4 choices.

Total possible different line-up of sections:

                     (2 x 3 x 3 x 4) = 72 different line-ups.

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A supply company manufactures masks and ventilators for hospitals. To maintain hugh quality, the company should not manufacture
notsponge [240]

Answer:

20 masks and 100 ventilators

Step-by-step explanation:

I assume the problem ask to maximize the profit of the company.

Let's define the following variables

v: ventilator

m: mask

Restictions:

m + v ≤ 120

10 ≤ m ≤ 50

40 ≤ v ≤ 100

Profit function:

P = 10*m + 65*v

The system of restrictions can be seen in the figure attached. The five points marked are the vertices of the feasible region (the solution is one of these points). Replacing them in the profit function:

point          Profit function:

(10, 100)    10*10 + 65*100 = 6600

(20, 100)    10*20 + 65*100 = 6700    

(50, 70)      10*50 + 65*70 =  5050

(50, 40)     10*50 + 65*40 = 3100

(10, 40)      10*10 + 65*40 =  2700

Then, the profit maximization is obtained when 20 masks and 100 ventilators are produced.

4 0
3 years ago
In a chemical plant, 24 holding tanks are used for final product storage. Four tanks are selected at random and without replacem
Damm [24]

Answer:

a) P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) = 0,7120   or 71,2 %

c) P(C) = 0,2055  or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )!    ⇒  C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!  

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2    ⇒  C ( 24,4) =  10626

TE = 10626

Splitting the group of tanks in two 6 with h-v  and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3)  = 6 * 18! / 3!*15!  =  18*17*16*15!/15!

FE =  4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607     or   P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2  = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120   or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

having 4 with t-i tanks is:

reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2    ⇒  FE = 2184

And again as the TE = 10626

P(C) = 2184/ 10626

P(C) = 0,2055  or P(C) = 20,55 %

5 0
3 years ago
Find the x-intercept of the line whose equation is 8x + 2y = 4.<br> 04<br> 02<br> 1/2
bezimeni [28]

Answer:

1/2

Step-by-step explanation:

The x-intercept is a point on the graph that is located on any point of x but must have a y-value of 0. To find the x-intercept, we must set y in the given equation equal to 0.

8x + 2y = 4

8x + 2(0) = 4

8x = 4

x = 4/8

x = 1/2

4 0
1 year ago
What is 2/10 as a percent
Wittaler [7]
2/10 as a percent would be 20%.
5 0
3 years ago
Read 2 more answers
Find the value of y, rounded to the nearest tenth. Please help me, I'd appreciate it!!
Blababa [14]
If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
</span><span>
y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4  </span>← to the nearest tenth<span>
</span><span>
</span>
8 0
2 years ago
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