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scZoUnD [109]
3 years ago
11

HELP PELASE ASAPppppp

Mathematics
1 answer:
hammer [34]3 years ago
6 0

Answer:

sin M = NK/MK = m/n

cos K = NK/MK = m/n

=> sin M/cos K = 1

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Pic below...........<br> ..............<br> look below
Kipish [7]

Answer:

3

Step-by-step explanation:

Factor the numerator and denominator and cancel the common factors.

7 0
4 years ago
Read 2 more answers
devon pays $49.95 for her roller skates. After that, she pays$5.95 for each visit to the roller rink. what is the greatest numbe
KatRina [158]

Answer:

about 11 times

Explanation: 120- 49.95= 70.5

70.5÷ 5.95= 11.7

7 0
3 years ago
(3x + 5y = 7<br> { 4x - y = 5
dalvyx [7]

Answer:

Step-by-step explanation:

Solution by substitution method

3x+5y=7

and 4x-y=5

Suppose,

3x+5y=7→(1)

and 4x-y=5→(2)

Taking equation (2), we have

4x-y=5

⇒y=4x-5→(3)

Putting y=4x-5 in equation (1), we get

3x+5y=7

⇒3x+5(4x-5)=7

⇒3x+20x-25=7

⇒23x-25=7

⇒23x=7+25

⇒23x=32

⇒x=32/23

→(4)

Now, Putting x=32/23

in equation (3), we get

y=4x-5

⇒y=4(32/23)-5

⇒y=(128-115)/23

⇒y=13/23

∴y=13/23   and x=32/23

5 0
2 years ago
A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar
Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0
3 years ago
How do you know whether an estimate of a product is an overestimate or an underestimate? Explain Please.
N76 [4]
You know if an answer is an over or underestimate because if the last 2 # is 5 and over, it is an overestimate. If the last 2 # is 4 and under, it is an underestimate. Ex: 345 answer if you were estimating 350 over
5 0
3 years ago
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