Answer:
your questions is wrong it's 2×2-6x=56
answer= X=-9
Step-by-step explanation:
2×2-6x=56
4-6x=56
-6x=56-4
-6x=54
-X=54/6
-X=9
X=-9
Y – y1 = m(x – x1)
y-(-1)=-5(x-2)
Y+1=-5(x-2)
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
Therefore
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
( using the property
)
( using the property 
( combining the like powers )
( using the property
)

( using the property
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is
is correct answer
The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane
Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0