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3 years ago

There are 2.54 centimeters in 1 inch. How many centimeters are there in 1 foot? In 1 yard? Explain your reasoning.

1 answer:

4 0

So if there are 2.54 cm in an inch that means that 1cm times 2.54=1 inch

there are 12 inches in a foot and 1 inch=2.54 centimter so
12 times 1 inch or 12 times 2.54=30.48 centimeters

there are 3 feet in a yard so we take the previous measurements and multiply

30.48cm in a foot times 3 feet in a yard or 30.48 times 3=91.44 cm in a yard

if you want to do it the long way, you can multiply 2.54 with 12 with 3 and get the same answer 91.44 cm in a yard

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This isosceles triangle has two sides of equal length, a, that are longer than the length of the base, b. The perimeter of the t

Ipatiy [6.2K]

B = base length
a = length of the other two equal sides

The value of 'a' is larger than the value of b. This is because the base is shorter than the other two equal sides. We're told that "one of the longer sides is 6.3 cm", meaning that a = 6.3

Replace every copy of 'a' in the given equation with 6.3; isolate b
2*a + b = 15.7
2*6.3 + b = 15.7
12.6 + b = 15.7
12.6 + b - 12.6 = 15.7 - 12.6 ... see note below
b = 3.1

note: I subtracted 12.6 from both sides. This is using the subtraction property of equality.

7 0

3 years ago

An unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6

SIZIF [17.4K]

Answer:

Probability of rolling at least 4 sixes is 0.01696.

Step-by-step explanation:

We are given that an unbalanced die is manufactured so that there is a 20% chance of rolling a “six." The die is rolled 6 times.

The above situation can be represented through binomial distribution;

$P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......$

where, n = number trials (samples) taken = 6 trials

r = number of success = at least 4

p = probability of success which in our question is probability of

rolling a “six", i.e; p = 0.20

Let X = Number of sixes on a die

So, X ~ Binom(n = 6, p = 0.20)

Now, Probability of rolling at least 4 sixes is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = P(X = 4) + P(X = 5) + P(X = 6)

= $\binom{6}{4} \times 0.20^{4} \times (1-0.20)^{6-4}+\binom{6}{5} \times 0.20^{5} \times (1-0.20)^{6-5}+\binom{6}{6} \times 0.20^{6} \times (1-0.20)^{6-6}$

= $15 \times 0.20^{4} \times 0.80^{2}+6 \times 0.20^{5} \times 0.80^{1}+1 \times 0.20^{6} \times 0.80^{0}$

= 0.0154 + 0.00154 + 0.000064

= 0.01696

Therefore, probability of rolling at least 4 sixes is 0.01696.

8 0

3 years ago

PLEASE HELP ME i’ll mark brainliest if you’re correct

AlladinOne [14]

Answer:

Step-by-step explanation:

Write an equation setting the lengths equal to each other.

5x + 3 = 2x + 9

Move the variable (x) to one side. I'm going to subtract 2x from both sides.

5x - 2x + 3 = 2x - 2x + 9

3x + 3 = 9

Subtract 3 from both sides

3x +3 - 3 = 9 - 3

3x = 6

Divide both sides by 3

3x/3 = 6/3

x = 2

Now use 2x + 9 to find the length of EG by substituting 2 in for x.

2x + 9

2(2) + 9

4 + 9

You could also use 5x + 3 to find the length of EG by substituting 2 in for x.

5 0

2 years ago

Read 2 more answers

Change the Cartesian Integral into an equivalent polar integral then evaluate the polar integral.

Elis [28]

Answer:

the ingegral I=π/4

Step-by-step explanation:

From the integral

I=∫0-1∫0-sqrt(1-y^2) (x^2 + y^2) dxdy

from polar coordinates

r²=x² + y²

then for r=1

√(1- y²) = x

for y=1 → x=0 , for y=0 → x=1

then the integration area is a hemisphere or radius r=1

therefore

I= ∫0-1∫0-sqrt(1-y^2) (x^2 + y^2) dxdy = (1/2)∫2π-0 ∫1-0 r² *r drdθ ( the additional r is due to the Jacobian of the transformation to polar coordinates , 1/2 because is an hemisphere so it would be the half of the value of the total sphere)

I= (1/2)∫2π-0 ∫1-0 r³drdθ = (1/2)∫2π-0 (1⁴/4 - 0⁴/4) dθ = (1/2)∫2π-0 (1/4)*dθ = (1/2)*(1/4)*2π = π/4

3 0

4 years ago

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nadezda [96]

Hey mate. Here is your answer.

Answer: D. The highlighted land is perfect for growing crops due to abundance of water.

Hope this helps!

4 0

4 years ago