Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
Kennedy did not distribute the 3 to the numbers in the parentheses.
Step-by-step explanation:
The simplified expression should be -3x+24.
Answer:
your answer will be <u>6</u><u>w</u><u>e</u><u>e</u><u>k</u><u>s</u><u> </u><u> </u><u> </u><u> </u>
<u>hope</u><u> </u><u>ur</u><u> </u><u>help</u>
Answer:68.27%
Step-by-step explanation:
TI84
2nd distr
normalcdf(89,97,93,4)