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2 years ago

Triangle \triangle A'B'C'△A

1 answer:

6 0

From the information given, the rotated triangle is same as the original triangle. This is because, vertices of the rotation remain at the origin - (0,0).

<h3>What is the proof the above?</h3>

Notice that the question states: △A'B'C' is the image of △ABC. Given that the △ without primes is the original and the one with primes depict the rotated triangle,

under a rotation about the origin, (0,0) (0,0) (0, 0), indicating no movement,

△A'B'C' is in the same position with △ABC.

Learn more about rotation at:
brainly.com/question/27915888
#SPJ1

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What is the answer to -6n^2 - 5n - 7 = -8

soldi70 [24.7K]

Answer:

n = $\frac{1}{3}$ , n = $\frac{1}{2}$

Step-by-step explanation:

6n² - 5n - 7 = - 8 ( add 8 to both sides )

6n² - 5n + 1 = 0 ← in standard form

Consider the product of the factors of the coefficient of the n² term and the constant term which sum to give the coefficient of the n- term

product = 6 × 1 = 6 and sum = - 5

The factors are - 3 and - 2

Use these factors to split the n- term

6n² - 3n - 2n + 1 = 0 ( factor the first/second and third/fourth terms )

3n(2n - 1) - 1(2n - 1) = 0 ← factor out (2n - 1) from each term

(2n - 1)(3n - 1) = 0 ← in factored form

Equate each factor to zero and solve for n

3n - 1 = 0 ⇒ 3n = 1 ⇒ n = $\frac{1}{3}$

2n - 1 = 0 ⇒ 2n = 1 ⇒ n = $\frac{1}{2}$

7 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

4 years ago

Raphael is enrolled as a foreign exchange student. He is from Canada and is going to attend school in Texas. His mother sent him

natita [175]

I pretty sure it would be 609.76

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3 years ago

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URGENTLY NEED THIS ASAP PLZ TYSM

Kazeer [188]

Answer:

fifth option

Step-by-step explanation:

Given

- 2(x - 5) ≤ 6x + 18 ← distribute left side

- 2x + 10 ≤ 6x + 18 ( subtract 6x from both sides )

- 8x + 10 ≤ 18 ( subtract 10 from both sides )

- 8x ≤ 8

Divide both sides by - 8, reversing the sign as a result of dividing by a negative quantity, thus

x ≥ - 1

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4 years ago

The students who went to summer camp voted for there favorite activities how many more students voted Viking than for fishing 21

Trava [24]

Simply subtract 21 from 9.

Your answer is 12 :)

5 0

4 years ago

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