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IRISSAK [1]
3 years ago
8

Help please !!!!!!!!!!!!!

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0
The answer is 3.....
2x+5
2x3+5=11      2x3=6
4x-1
4x3-1=11       4x3=12
You might be interested in
5) Solve: 2.4p + 6 = 48​
KatRina [158]

Answer:

p = 17.5

Step-by-step explanation:

This is the answer because:

1) First, we have to isolate x

2) To isolate x, first -6 from +6 and 48

+6 - 6 = 0

48 - 6 = 42

Equation: 2.4p = 42

3) Now we are left with 2.4p = 42

4) Next, divide 2.4 from 2.4 and 42

2.4/2.4 = 0

42/2.4 = 17.5

5) We are left with

p = 17.5

Therefore, the answer is p = 17.5

Hope this helps!

3 0
3 years ago
This assignment is due tomorrow please help :(
Mariulka [41]
The answer would be 9 units squared hope this helped(:
6 0
3 years ago
Read 2 more answers
what is the number Chef Alonso should multiply the amount of chicken by so that the recipe will make two full servings each with
timama [110]
Divide by 2        is the answer
                                                             
5 0
3 years ago
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
Task 1:
OleMash [197]

Answer:

maximum height is 4.058 metres

Time in air = 0.033 second

Step-by-step explanation:

Given that the equation height h

h = -212t^2 + 7t + 4

What is the toy's maximum height?

Let us assume that the equation is a perfect parabola

Time t at Maximum height will be

t = -b/2a

Where b = 7 and a = - 212

t = -7/ - 212 ×2

t = 7/ 424 = 0.0165s

Substitute t in the main equation

h = - 212(7/424)^2 + 7(7/424) + 4

h = - 0.05778 + 0.115567 + 4

h = 4.058 metres

Therefore the maximum height is 4.058 metres

How long is the toy in the air?​

The object will go up and return to the ground.

At ground level, h = 0

-212t^2 + 7t + 4 = 0

212t^2 - 7t - 4 = 0

You can factorize the above equation and pick the positive time t since time can't be negative

Or

Since we have assumed that it's a perfect parabola,

Total time in air = (-b/2a) × 2

Time in air = 0.0165 × 2 = 0.033 s

3 0
3 years ago
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