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IRISSAK [1]
3 years ago
8

Help please !!!!!!!!!!!!!

Mathematics
1 answer:
cupoosta [38]3 years ago
7 0
The answer is 3.....
2x+5
2x3+5=11      2x3=6
4x-1
4x3-1=11       4x3=12
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Could someone please help me on this question
xeze [42]

the answer is 8! hope that helps


3 0
3 years ago
RV=y+27 and TV=3y–17, find RV in parallelogram RSTU.<br> T<br> S<br> R<br> U<br> V
zaharov [31]

Answer:

RV = 49 units

Step-by-step explanation:

in parallelogram RSTU , the diagonals bisect each other, then

TV = RV , that is

3y - 17 = y + 27 ( subtract y from both sides )

2y - 17 = 27 ( add 17 to both sides )

2y = 44 ( divide both sides by 2 )

y = 22

Then

RV = y + 27 = 22 + 27 = 49 units

6 0
1 year ago
explain why the function f(x)= 5x-15/x-3 is not asymptotic to the line x=3. sketch the graph of this function.
Katyanochek1 [597]
X=3 is a vertical line . The question is "Is this line a vertical asymptotefor the function f(x)?". Vertical asymptote is vertical line near which the function grows without bound.
The function f(x)=5x-15/x-3 is not asymptotic to the line x=3, because for x=3 f(x)=5*3-15/3-3=0/0=0 . So, there is a value for x=3 and the function f(x) does not grow near x=3 without bound.

3 0
3 years ago
Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%
BaLLatris [955]
We're looking for an integrating factor \mu(x,y)=x^py^q such that

\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0

is exact, which would require that

(\mu M)_y=(\mu N)_x
(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x
49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q
\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4

You can verify that (\mu M)_y=(\mu N)_x if you'd like. With the ODE now exact, we have a solution F(x,y)=C such that

F_x=\mu M
F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx
F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)

F_y=\mu N
50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4
f'(y)=0
\implies f(y)=C

and so the general solution is

F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C
8 0
3 years ago
Real world scenario in which 12 fluid ounces would be converted into liters
guajiro [1.7K]
When baking and you need to know whether you have to buy a half a gallon or a gallon:)
7 0
2 years ago
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