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3 years ago

Help please !!!!!!!!!!!!!

Mathematics

1 answer:

cupoosta [38]3 years ago

7 0

The answer is 3.....
2x+5
2x3+5=11 2x3=6
4x-1
4x3-1=11 4x3=12

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Could someone please help me on this question

xeze [42]

the answer is 8! hope that helps

3 0

3 years ago

RV=y+27 and TV=3y–17, find RV in parallelogram RSTU. T S R U V

zaharov [31]

Answer:

RV = 49 units

Step-by-step explanation:

in parallelogram RSTU , the diagonals bisect each other, then

TV = RV , that is

3y - 17 = y + 27 ( subtract y from both sides )

2y - 17 = 27 ( add 17 to both sides )

2y = 44 ( divide both sides by 2 )

y = 22

Then

RV = y + 27 = 22 + 27 = 49 units

6 0

1 year ago

explain why the function f(x)= 5x-15/x-3 is not asymptotic to the line x=3. sketch the graph of this function.

Katyanochek1 [597]

X=3 is a vertical line . The question is "Is this line a vertical asymptotefor the function f(x)?". Vertical asymptote is vertical line near which the function grows without bound.
The function f(x)=5x-15/x-3 is not asymptotic to the line x=3, because for x=3 f(x)=5*3-15/3-3=0/0=0 . So, there is a value for x=3 and the function f(x) does not grow near x=3 without bound.

3 0

3 years ago

Consider the implicit differential equation <img src="https://tex.z-dn.net/?f=%2849%20y%5E%7B3%7D%20%2B%2045%20xy%29%20dx%20%2B%

BaLLatris [955]

We're looking for an integrating factor $\mu(x,y)=x^py^q$ such that

$\mu\underbrace{(49y^3+45xy)}_M\,\mathrm dx+\mu\underbrace{(98xy^2+50x^2)}_N\,\mathrm dy=0$

is exact, which would require that

$(\mu M)_y=(\mu N)_x$
$(49x^py^{q+3}+45x^{p+1}y^{q+1})_y=(98x^{p+1}y^{q+2}+50x^{p+2}y^q)_x$
$49(q+3)x^py^{q+2}+45(q+1)x^{p+1}y^q=98(p+1)x^py^{q+2}+50(p+2)x^{p+1}y^q$
$\implies\begin{cases}49(q+3)=98(p+1)\\45(q+1)=50(p+2)\end{cases}\implies p=\dfrac52,q=4$

You can verify that $(\mu M)_y=(\mu N)_x$ if you'd like. With the ODE now exact, we have a solution $F(x,y)=C$ such that

$F_x=\mu M$
$F=\displaystyle\int(49y^3+45xy)x^{5/2}y^4\,\mathrm dx$
$F=10x^{9/2}y^5+14x^{7/2}y^7+f(y)$

$F_y=\mu N$
$50x^{9/2}y^4+98x^{7/2}y^6+f'(y)=98x^{7/2}y^2+50x^{9/2}y^4$
$f'(y)=0$
$\implies f(y)=C$

and so the general solution is

$F(x,y)=10x^{9/2}y^5+14x^{7/2}y^7=C$

8 0

3 years ago

Real world scenario in which 12 fluid ounces would be converted into liters

guajiro [1.7K]

When baking and you need to know whether you have to buy a half a gallon or a gallon:)

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2 years ago