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Alja [10]
3 years ago
5

What is the perimeter of this triangle?

Mathematics
1 answer:
Sholpan [36]3 years ago
4 0

Answer:

Step-by-step explanation: what triangle?

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Simplify the expression by combining like terms. 7w+9+6X
Mars2501 [29]

Answer:

Step-by-step explanation:

the answer stay the same due to the fact there are no like terms

7w+9+6x

8 0
3 years ago
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Please explain how to do this well I really need help
astraxan [27]
Simply the radical expression
6 0
3 years ago
One of the earliest applications of the Poisson distribution was in analyzing incoming calls to a telephone switchboard. Analyst
grandymaker [24]

Answer:

(a) P (X = 0) = 0.0498.

(b) P (X > 5) = 0.084.

(c) P (X = 3) = 0.09.

(d) P (X ≤ 1) = 0.5578

Step-by-step explanation:

Let <em>X</em> = number of telephone calls.

The average number of calls per minute is, <em>λ</em> = 3.0.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 3.0.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,3...

(a)

Compute the probability of <em>X</em> = 0 as follows:

P(X=0)=\frac{e^{-3}3^{0}}{0!}=\frac{0.0498\times1}{1}=0.0498

Thus, the  probability that there will be no calls during a one-minute interval is 0.0498.

(b)

If the operator is unable to handle the calls in any given minute, then this implies that the operator receives more than 5 calls in a minute.

Compute the probability of <em>X</em> > 5  as follows:

P (X > 5) = 1 - P (X ≤ 5)

              =1-\sum\limits^{5}_{x=0} { \frac{e^{-3}3^{x}}{x!}} \,\\=1-(0.0498+0.1494+0.2240+0.2240+0.1680+0.1008)\\=1-0.9160\\=0.084

Thus, the probability that the operator will be unable to handle the calls in any one-minute period is 0.084.

(c)

The average number of calls in two minutes is, 2 × 3 = 6.

Compute the value of <em>X</em> = 3 as follows:

<em> </em>P(X=3)=\frac{e^{-6}6^{3}}{3!}=\frac{0.0025\times216}{6}=0.09<em />

Thus, the probability that exactly three calls will arrive in a two-minute interval is 0.09.

(d)

The average number of calls in 30 seconds is, 3 ÷ 2 = 1.5.

Compute the probability of <em>X</em> ≤ 1 as follows:

P (X ≤ 1 ) = P (X = 0) + P (X = 1)

             =\frac{e^{-1.5}1.5^{0}}{0!}+\frac{e^{-1.5}1.5^{1}}{1!}\\=0.2231+0.3347\\=0.5578

Thus, the probability that one or fewer calls will arrive in a 30-second interval is 0.5578.

5 0
3 years ago
What is the growth factor of the following example? Assume time is measured in the units given.
My name is Ann [436]

Answer:

B. 0.20 per century

Step-by-step explanation:

I calculated it logically

8 0
3 years ago
If a coin is flipped 20 times and a head comes up 7 times, what is the relative frequency of a head coming up?
Tju [1.3M]
Relative frequency is the absolute frequency (i.e. the number of times of the wanted result) divided by the total  number of events.

In this case you have to calculate: the number of heads that came up divided by the number of times the coin was flipped.

Number of times the coin was flipped: 20
Numbef of times head came up: 7

Relative frequency: 7 / 20 = 0.35, which is the option B.
7 0
3 years ago
Read 2 more answers
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