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Archy [21]
2 years ago
6

Prove the following identity. [sin(x+y)+sin(x-y)]/[cos(x+y)+cos(x-y)] = tan(x)

Mathematics
1 answer:
tia_tia [17]2 years ago
4 0
\frac{sin(x + y) + sin(x - y)}{cos(x + y) + cos(x - y)} = tan(x)
\frac{(sin(x)cos(y) + cos(x)sin(y)) + (sin(x)cos(y) - cos(x)sin(y))}{(cos(x)cos(y) - sin(x)sin(y)) + (cos(x)cos(y) + sin(x)sin(y))} = tan(x)
\frac{(sin(x)cos(y) + sin(x)cos(y)) + (cos(x)sin(y) - cos(x)sin(y))}{(cos(x)cos(y) + cos(x)cos(y)) + (-sin(x)sin(y) + (sin(x)sin(y))} = tan(x)
\frac{2sin(x)cos(y)}{2cos(x)cos(y)} = tan(x)
\frac{sin(x)}{cos(x)} = tan(x)
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