The factored expression of m(2a+b)-n(2a+b)+2n(2a+b) is (m + n)(2a + b)
<h3>How to factor the expression?</h3>
The expression is given as:
m(2a+b)-n(2a+b)+2n(2a+b)
Factor out 2a + b
m(2a+b)-n(2a+b)+2n(2a+b) = (m - n + 2n)(2a + b)
Evaluate the like terms
m(2a+b)-n(2a+b)+2n(2a+b) = (m + n)(2a + b)
Hence, the factored expression of m(2a+b)-n(2a+b)+2n(2a+b) is (m + n)(2a + b)
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Answer:
nonrigid and segement lengths
Step-by-step explanation:
Factor the numerator using difference of cubes:
a = x
b = 2
Now you can evaluate limit as x=2.
Answer:
90°
Step-by-step explanation:
Actually the question should be AC is tangent to circle B at point C. What is the measure of angle BCA.
AC is tangent and BC is radius.
Radius is perpendicular to the tangent.
Therefore,
measure of angle BCA = 90°
