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Advocard [28]
3 years ago
10

in simba the temperature was 6°c in the morning on a particular day . What was the temperature during the night if it further dr

opped by 9°c​
Mathematics
1 answer:
Lana71 [14]3 years ago
5 0

Given parameters:

Simba temperature in the morning  = 6°C

Temperature drop = 9°C

Unknown:

Temperature during the night = ?

Solution:

 Since the temperature in the morning is given;

 Temperature at night  = Morning temperature  - drop in temperature

  Temperature at night = 6°C - 9°C = -3°C

The temperature at night is  -3°C

       

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Answer:

B is the correct answer.

Step-by-step explanation:

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3 years ago
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2 years ago
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PLEASE HELP ME OUT !!! WILL APPRECIATE IT SO MUCH !!
mash [69]
Start with the general formula. The key word is difference. So the general formula is 

D(x) = W(x) - R(x) Now substitute in the values for W(x) and R(x)
D(x) = 0.002x^3 - 0.01x^2 - (x^2 - 4x  + 13) Be very careful about the sign in front of the brackets.

D(x) = 0.002x^3 - 0.01x^2 - x^2 + 4x - 13 Do you see what that minus sign did? It affected all 3 terms.

D(x) = 0.002x^3 - 1.01x^2 + 4x - 13 <em>Note: -0.01 - 1x^2 = - 1.01 x^2</em>
That gives you a clear cut answer

C<<<<< answer.

That sign is the worst part of the question. Make sure you understand what it did.
4 0
3 years ago
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