Question

Steve can afford a $330 per month car payment. If he is being offered a 6 year car loan with an APR of 1.2%, compound monthly, what is the value of the most expensive car he can afford?

Answer 1

Answer:

The value of most expensive car he can afford is $ 22913.757.

Step-by-step explanation:

Since, the periodic payment of a loan is,

$P=\frac{r(PV)}{1-(1+r)^{-n}}$

Where, P.V. is the presents value of the loan,

r is the rate per period,

n is the number of periods,

Here, Monthly payment, P = $ 330,

⇒ The loan is compound monthly,

Thus, if the time = 6 years,

The number of periods, n = 6 × 12 = 72 months, ( 1 year = 12 months ),

Also, the A.P.R = 1.2 % = 0.012

So, the rate per periods,

$r=\frac{0.012}{12}$

By substituting the values,

$330=\frac{\frac{0.012}{12}(PV)}{1-(1+\frac{0.012}{12})^{-72}}$

$\implies x = 22913.757$

Hence, the value of most expensive car he can afford is $ 22913.757.

Answer 2

Answer:22,913.76

Step-by-step explanation: