C=(1/4)*circumference
Area=pq+3.142r^2
60*3.142=pq+3.142p^2
q=((1/4)*2p*3.142)+2*3.142
q=1.571p+6.284
188.52=1.571p^2+6.284p+3.142p^2
188.52=4.713p^2+6.284p
188520=4713p^2+6284p
28÷514=0.
514÷28=18.
Partial Quotients
Answer:
Step-by-step explanation:
The first two steps are for the purpose of eliminating fractions. Doing so results in 4(2x - 5) = 9(x - 2), which is to be solved for x.
Perform the indicated multiplication, obtaining:
8x - 20 = 9x - 18.
Then combine like terms: -2 = x, or
x = -2.
To complete the formal check, substitute -2 for x in the first equation. This results in:
(1/3)(-4 - 5) = (3/4)(-2 -2), or
-3 = -3
... which is obviously true.
Step-by-step explanation:
-0.45 = 9/20
2.77= 2 7/9
5.55 = 5 5/9
The variable is b, the coefinet is 1/3
remember
ab-ac=a(b-c)
1/3b-1/3=1/3(b-1)
there, factored
