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pav-90 [236]
2 years ago
11

I need help with this problem!! I need it answered by 11:59 tonight.

Mathematics
1 answer:
tino4ka555 [31]2 years ago
7 0
OOP sorry did you get it
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A girl successfully made 12 free throws yesterday today she made 150% as a nanny how many successful Fritos did she make today
Bas_tet [7]

Answer:

18 throws

Step-by-step explanation:

Given data

Number of throws= 12

Let us 150% if 12

=150/100*12

=1.5*12

=18 throws

Hence she made 18 throws today

6 0
2 years ago
A cola-dispensing machine is set to dispense 8 ounces of cola per cup, with a standard deviation of 1.0 ounce. The manufacturer
pshichka [43]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is X: ounces per cup dispensed by the cola-dispensing machine.

The population mean is known to be μ= 8 ounces and its standard deviation σ= 1.0 ounce. Assuming the variable has a normal distribution.

A sample of 34 cups was taken:

a. You need to calculate the Z-values corresponding to the top 5% of the distribution and the lower 5% of it. This means you have to look for both Z-values that separates two tails of 5% each from the body of the distribution:

The lower value will be:

Z_{o.o5}= -1.648

You reverse the standardization using the formula Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~N(0;1)

-1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 7.72ounces

The lower control point will be 7.72 ounces.

The upper value will be:

Z_{0.95}= 1.648

1.648= \frac{X[bar]-8}{\frac{1}{\sqrt{34} } }

X[bar]= 8.28ounces

The upper control point will be 8.82 ounces.

b. Now μ= 7.6, considering the control limits of a.

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-7.6)/(1/√34))- P(Z≤7.72-7.6)/(1/√34))

P(Z≤7.11)- P(Z≤0.70)= 1 - 0.758= 0.242

There is a 0.242 probability of the sample means being between the control limits, this means that they will be outside the limits with a probability of 1 - 0.242= 0.758, meaning that the probability of the change of population mean being detected is 0.758.

b. For this item μ= 8.7, the control limits do not change:

P(7.72≤X[bar]≤8.28)= P(X[bar]≤8.28)- P(X[bar]≤7.72)

P(Z≤(8.28-8.7)/(1/√34))- P(Z≤7.72-8.7)/(1/√34))

P(Z≤-2.45)- P(Z≤-5.71)=0.007 - 0= 0.007

There is a 0.007 probability of not detecting the mean change, which means that you can detect it with a probability of 0.993.

I hope it helps!

5 0
2 years ago
Read 2 more answers
Use properties to find the sum or product of 93+(68+7)
zaharov [31]
93 + (68 + 7)
93 + 75
168
7 0
3 years ago
Is this correct? If not, please tell me the correct answer!!!
White raven [17]

Answer:

That is correct

Step-by-step explanation:

180° rotation about origin just means that you have to flip the pre-existing image across the x-axis

Good job!

3 0
3 years ago
Tracy deposited $59 into a bank account that earned 3.5% simple interest each year.
AnnyKZ [126]

Answer:

Step-by-step explanation:

1) Tracy:

  P =$ 59 ;  r =3.5% ; T = 12 years

SI = PrT/100

      = 59 * 3.5 * 12 /100

      = $24.78

Amount Tracy that will be after 12 years in her account   = $ 59 +$24.78

              = $83.78

6 0
3 years ago
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