Timothy puts $1,500 into a savings account. He receives a
2 answers:
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Answer:
We conclude that the percentage of blue candies is equal to 29%.
Step-by-step explanation:
We are given that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%.
Let p = <u><em>population percentage of blue candies</em></u>
So, Null Hypothesis, : p = 29% {means that the percentage of blue candies is equal to 29%}
Alternate Hypothesis, : p
29% {means that the percentage of blue candies is different from 29%}
The test statistics that will be used here is <u>One-sample z-test for</u> <u>proportions</u>;
T.S. = ~ N(0,1)
where, = sample proportion of blue coloured candies = 28%
n = sample of colored candies = 100
So, <u><em>the test statistics</em></u> =
= -0.22
The value of the z-test statistics is -0.22.
<u>Also, the P-value of the test statistics is given by;</u>
P-value = P(Z < -0.22) = 1 - P(Z 0.22)
= 1 - 0.5871 = 0.4129
Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.
Since the value of our test statistics lies within the range of critical values of z, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.
Therefore, we conclude that the percentage of blue candies is equal to 29%.
Answer:
Her hourly rate is <u>$14</u>.
Step-by-step explanation:
Given:
Penelope goes to work after school for 4.5 hours on Mondays, Tuesdays, and Fridays.
She works 8 hours each on Wednesdays or Thursdays.
Now, to find her hourly rate.
So, total hours Penelope work on Mondays, Tuesdays, and Fridays:
And, total hours she work on Wednesdays and Thursdays:
Now,<em><u> the total hours each week she work:</u></em>
<u><em>Total money she makes each week</em></u> = $413.
Now, to get the hourly rate we divide the total hours each week she work by total money she makes each week:
Therefore, her hourly rate is $14.