In y = mx+b, m is the term that refers to slope
hope this helps
Answer:
64√2 or 64 StartRoot 2 EndRoot
Step-by-step explanation:
A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.
Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.
X=(128√2)/2= 64√2 cm.
Since X is the leg, the answer would be 64√2
The missing steps are each right angles and
.
Solution:
Step 1: Given data:



Step 2: In the two polygons,
and 
(Each right angle)
Step 3: Given

Step 4: By third angle theorem,
If two angles in one triangle are congruent to the two angles in the other triangle, then the third angles in the triangles also congruent.

Step 5: By the definition of congruent polygons,
If two same shape polygons have all the angles are congruent and all the corresponding sides are congruent then the polygons are congruent.
Hence
.
Therefore the missing steps are each right angles and
.
They are the same, because there's an invisible 0 next to 0.6.....