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Mariana [72]
3 years ago
7

Which polygon is always irregular

Mathematics
1 answer:
zvonat [6]3 years ago
9 0
Pentagons and hexagons can be irregular.

Anything that does not have congruent sides is irregular.

Hope that helped :))
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How to write 8÷2×(5+5) in words​
Ivenika [448]

Eight divided by two times (5 plus 5)

6 0
3 years ago
Read 2 more answers
A raffle has a grand prize of a European cruise valued at $10000 with a second prize of a Rocky Point vacation valued at $700. I
lisov135 [29]

Answer:

- 3.027

Step-by-step explanation:

First price = 10000 ; second price = 700

Number of tickets sold = 11000

Ticket cost = $4

Probability that a ticket wins grand price = 1 / 11000

Probability that a ticket wins second price = 1 / 11000

X ____ 10000 _____ 700

P(x) ___ 1 / 11000 ___ 1/11000

Expected winning for a ticket buyer :

E(X) = Σx*p(x)

E(X) = (1/11000 * 10000) + (1/11000 * 700) - ticket cost

E(X) = 0.9090909 + 0.0636363 - 4

E(X) = - 3.0272728

E(X) = - 3.027

8 0
3 years ago
Expand . ( 3x –2 ) 2 please help me with this.
Ainat [17]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{9x}^2\textsf{ - 12x + 4}

-------------------------------------------------------------------------------------------------------------

Given:  \textsf{(3x - 2)}^2

Find: \textsf{Simplify the expression}

Solution:  It looks like 2 is at the end of the parenthesis where the power would be instead of distributing the number.  If so the following steps would be followed.

<u>Expand</u>

  • \textsf{(3x - 2)}^2
  • \textsf{(3x - 2)(3x - 2)}
  • \textsf{(3x * 3x) + (3x * (-2)) + (3x * (-2)) + (-2 * (-2))}

<u>Simplify</u>

  • \textsf{9x}^2\textsf{ - 6x - 6x + 4}
  • \textsf{9x}^2\textsf{ - 12x + 4}

Therefore, after following the provided information we are able to determine that the expanded form would be 9x^2 - 12x + 4.

3 0
2 years ago
Read 2 more answers
20 POINTS!!
Whitepunk [10]
Congruent means they are the same size 

To prove the two triangles are congruent you would need to know the length of at least two of the sides. If two sides were not known you would need to know the length of one side and at least one of the unknown angles.
3 0
4 years ago
5. The sum of two integers is (-8). Their product is (+7). What are the two<br> integers?
egoroff_w [7]

Answer:

Step-by-step explanation:

Let one number = x

The other  number = (-8) - x

Their product  = 7

x*( -8 - x) = 7

x*(-8) - x*x = 7

-8x - x² = 7

0 = 7 + 8x + x²

x² + 8x + 7 = 0

x² + 7x +x +7 = 0

x(x + 7) + (x+7) = 0

(x + 7)(x + 1) = 0

x + 7 = 0   ;x + 1 = 0

x = -7         ; x = -1

The two integers are: (-7) and (-1)

6 0
3 years ago
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