Write an equation a) in point-slope form b) in slope-intercept form c) find the y-

Please help! I’ll also give brainliest! Thank you!

love history [14]

Answer:

{1,9,7,5,2}

Step-by-step explanation:

Those are the answers

6 0

3 years ago

Read 2 more answers

Antonia picks one card from a set of three cards. The cards are a king (K), a queen (Q), and a jack (J). She then spins a spinne

Zielflug [23.3K]

white black red

king K-W K-B K-R

queen Q-W Q-B Q-R

jack J-W J-B J-R

Please mark as brainlist!

4 0

3 years ago

Help me need to know

crimeas [40]

Answer:i am confused what is the question i will help tho

Step-by-step explanation:

3 0

3 years ago

A store manager timed Janette to see how long it would take her to fold and put away a sweater, a shirt, a pair of pants, and a

Andru [333]

25.35 seconds. Add all 4 numbers and divide by 4

8 0

3 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

so

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

so

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

so

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

so

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

so

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

so

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago