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3 years ago

10

a countertop is 16 feet long and 3 feet wide tile cost $20 per square meter how much will it cost to cover the countertop with n

ew tile

1 answer:

Sedbober [7]3 years ago

8 0

The counter top is 48 square feet (16x3) and there are 4.45935 square meters in 1 square foot... So I think about $90... I Hope this helps :)

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Fifty elk are introduced into a game preserve. It is estimated that their population will increase according to the model

Charra [1.4K]

Answer:

ok ok ok chilll The answer is

Step-by-step explanation:

4 0

3 years ago

The results from a random sample of 150 students' after-school activities at a school are shown. 68 students prefer soccer. 59 s

VladimirAG [237]

Answer:

≈ 197 students

Step-by-step explanation:

Let's start by writing what we know.

150 students sampled

68 prefer soccer

59 prefer basketball

23 prefer swimming

Part A

If 59 students prefer basketball out of the 150 students sampled then we divide 59/150 in order to get the percentage of students that prefer basketball.

59/150 ≈ 39.33% Remember this is only a sample of the students so it is approximate.

Now that we have the percentage, we can multiply it by the entire student body to get an approximate number of all students that prefer basketball.

39.33% = .3933

.3933 * 500 = 196.66 ≈ 197 students (because we can't have a partial student we round up)

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3 years ago

Which statement about this data distribution is NOT true?

MrRa [10]

Answer:

c is the correct answer brainliest plz

5 0

3 years ago

Here are six cards arrange the card into three pairs with the same total -4 -2 -1 5 6 8

NeX [460]

8,-4

6,-2

and

5,-1

They all will equal 4. Hope this helps.

6 0

3 years ago

Read 2 more answers

Find the smallest possible value of$$\frac{(y-x)^2}{(y-z)(z-x)} \frac{(z-y)^2}{(z-x)(x-y)} \frac{(x-z)^2}{(x-y)(y-z)},$$where $x

Harlamova29_29 [7]

Answer:

$\frac{(y-x)^2}{(x-y)^2} \frac{(x-z)^2}{(z-x)^2}\frac{(z-y)^2}{(y-z)^2} =1$

And on this case the samllest possible value would be 1

Step-by-step explanation:

For this case we have the following expression:

$\frac{(y-x)^2}{(y-z)(z-x)} \frac{(z-y)^2}{(z-x)(x-y)} \frac{(x-z)^2}{(x-y)(y-z)}$

And we can rewrite this expression like this:

$\frac{(y-x)^2}{(x-y)^2} \frac{(x-z)^2}{(z-x)^2}\frac{(z-y)^2}{(y-z)^2}$

For this case is important to remember the following property from algebra:

$(a-b)^2 = a^2 -2ab + b^2$

$(b-a)^2 = b^2 - 2ab + a^2$

On this case we can see that $(a-b)^2 = (b-a)^2$

So then $(y-x)^2 = (x-y)^2 , (x-z)^2= (z-x)^2, (z-y)^2 =(y-z)^2$

So then we can simplify all the expression and we got this:

$\frac{(y-x)^2}{(x-y)^2} \frac{(x-z)^2}{(z-x)^2}\frac{(z-y)^2}{(y-z)^2} =1$

And on this case the samllest possible value would be 1

3 0

3 years ago