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sattari [20]
3 years ago
6

If Nicholas spends $8.10 on pixie sticks how many pounds did he purchase. Pixie sticks $4.50 per pound show word. Jane measure $

9.75 worth of jolly ranchers how many pounds did she buy Jolly ranchers $3.25per pound
Mathematics
2 answers:
Ira Lisetskai [31]3 years ago
8 0

Answer:

Nicholas bought 1.8 lbs, and Jane bought 3lbs.

Step-by-step explanation:

Divide the total amount by how much it is per pound, so 8.10 divided by 4.50 = 1.8 and 9.75 divided by 3.25= 3

Ivahew [28]3 years ago
8 0

Answer:

Nicholas has purchased 1.8 pounds of pixie sticks.

Jane has purchased 3.0 pounds of Jolly ranchers.

Step-by-step explanation:

Cost of 1 pounds of pixie sticks = $4.50

Let the number of pixie sticks = x

Total  money spend on x pounds of pixie sticks = $8.10

\$4.50\times x=\$8.10

x=\frac{\$8.10}{\$4.50}=1.8 pounds

Nicholas has purchased 1.8 pounds of pixie sticks.

Cost of 1 pounds of Jolly ranchers = $3.25

Let the number of Jolly ranchers = y

Total  money spend on y pounds of Jolly ranchers = $9.75

\$3.25\times y=\$9.75

x=\frac{\$9.75}{\$3.25}=3.0 pounds

Jane has purchased 3.0 pounds of Jolly ranchers.

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General Formulas and Concepts:

<u>Algebra I</u>

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Step-by-step explanation:

In order for a systems of equations to have a solution set, the 2 graphs must intersect at at least 1 point. Here, we see that graphs 1 and 5 do not intersect each other at all.

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Brainliest to first correct answer
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Smallest surface area is of Cuboid B i.e 440 cm²

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Step-by-step explanation:

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The formula used is: Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)

Putting values and finding surface area:

Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((6 \times 25)+(25 \times 4)+(6 \times 4))\\Surface \ Area \ of \ Cuboid=2(150+100+24)\\Surface \ Area \ of \ Cuboid=2(274)\\Surface \ Area \ of \ Cuboid=548\: cm^2

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Surface Area of Cuboid B:

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The formula used is: Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)

Putting values and finding surface area:

Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2(10 \times 6)+(6 \times 10)+(10 \times 10))\\Surface \ Area \ of \ Cuboid=2(60+60+100)\\Surface \ Area \ of \ Cuboid=2(220)\\Surface \ Area \ of \ Cuboid=440\: cm^2

So, Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C:

Length = 2

Breadth = 20

Height = 15

The formula used is: Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)

Putting values and finding surface area:

Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((2 \times 20)+(20 \times 15)+(2 \times 15))\\Surface \ Area \ of \ Cuboid=2(40+300+30)\\Surface \ Area \ of \ Cuboid=2(370)\\Surface \ Area \ of \ Cuboid=740\: cm^2

So, Surface Area of Cuboid C = 740 cm²

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Surface Area of Cuboid A = 548 cm²

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Surface Area of Cuboid C = 740 cm²

The company wants to choose the design having smallest surface area.

So, smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

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