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2 years ago

Manuel and Peter are standing 12 ft. apart from each other and looking up at a kite that is

Mathematics

1 answer:

deff fn [24]2 years ago

8 0

68.1 ft is the answer

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The radius of a cylindrical water tank is 4.5 ft, and its height is 8 ft. What is the volume of the tank?

Brums [2.3K]

The answer is 509 ft^3

Formula:
V = πr^2h
V = 3.14 * 4.5^2 * 8
V = 3.14 * 20.25 * 8
V = 508.68 ft^3

508.68 rounded to the nearest whole number is 509

So the volume of the cylinder is 509 ft^3

5 0

2 years ago

Simplify the expression. n+ 3(n + 1) = 0

laila [671]

Answer:

n=-3/4

Step-by-step explanation:

4 0

2 years ago

All furniture orders over $100 have a flat shipping fee of $35. If the order is $437.50, what percent is the shipping and handli

Fynjy0 [20]

Answer: 8%

Step-by-step explanation:The shipping and handling fee of $35 was applied to the order or $437.50.

Divide the total by the shipping and handling fee:

35 / 437.50 = .08

Multiply by 100 to get percent:

.08 x 100 = 8%

8 0

2 years ago

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0

2 years ago

2|4x-1|=38 I need to solve this

umka21 [38]

First you have to have the absolute value isolated so the 2 has to be divided. Then set up the two cases and solve.

5 0

2 years ago