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dexar [7]
3 years ago
14

Hector planted 185 flowery in two days there were five volunteers including Hector who each planter about the same Number of flo

wers about how many flowers did they plant
Mathematics
1 answer:
exis [7]3 years ago
6 0
<span>you take 185 and divide it by 5. Then you take your answer from there, 37, and that would be your answer if you were trying to find out how many flowers each volunteer planted over the two days. If you want to know how many flowers each volunteer planted each day, you would divide 37 by two. Then your answer is that each planter planted 18 to 19 flowers each day, since you can't plant 18.5 flowers each day!</span>
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Plz help asap thank youuu
wariber [46]

Answer:

1. y = 0, b/a

2. y =  0, a/b

3. y =0, c/b

4. y =0, c/a

Step-by-step explanation:

The slope formula for y = mx + b which is known as standard form is Ax + By ≥ C

slope = A/B

x-intercept = C/A

y-intercept = C/B

and now we are dueling with y, so we will use y-intercept

1. cx + ay = b

where c is x, a = y and b=c

Y-int = C/B

y = 0, b/a

2. cx + by = a

y =  0, a/b

3. ax + by = c

y =0, c/b

4. bx+ ay = c

y =0, c/a

Hope this helps

7 0
3 years ago
Leo bought a car for x dollars one year later the value of the car was 0.88x.which exspression is another way to describe the ch
Furkat [3]
Well, the car depreciated in value by 12%, so you could say
x-12%, or just
x-0.12.
5 0
3 years ago
How do you identify the opposite and the absolute value of a rational number
Sergeeva-Olga [200]

Rational numbers are the numbers that can be written as the fraction of two integers and absolute value is the distance a number is away from 0. If we look at a number line, the absolute value is the distance any number on the number line is away from 0. Distance is always positive, so our absolute value is always 0.

8 0
3 years ago
Consider the following information related to a set of quantitative sample data:
svlad2 [7]

Answer:

(a) There are outliers

(b) x and x >62

Step-by-step explanation:

Given

\sigma = 14.92

\bar x = 22.0

q_0 = -24

q_1 = 14.5

q_2 = 24.5

q_3 = 33.5

q_4 = 64

Solving (a): Check for outliers

This is calculated using:

Lower = Q_1 - (1.5 * IQR) --- lower bound of outlier

Upper = Q_3 +(1.5 * IQR) --- upper bound of outlier

Where

IQR = Q_3 - Q_1

So, we have:

IQR = 33.5 - 14.5

IQR = 19

The lower bound of outlier becomes

Lower = Q_1 - (1.5 * IQR)

Lower = 14.5 - (1.5 * 19)

Lower = 14.5 - 28.5

Lower = -14

The upper bound of outlier becomes

Upper = Q_3 +(1.5 * IQR)

Upper = 33.5 + 1.5 * 19

Upper = 33.5 + 28.5

Upper = 62

So, we have:

-14 \le x \le 62 --- the range without outlier

Given that:

q_0 = -24  --- This represents the lowest data

q_4 = 64   --- This represents the highest data

-24 and 64 are out of range of -14 \le x \le 62.

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

x and x >62

4 0
2 years ago
What is 1 + 1???????????????????????????????????????????????????
choli [55]
Answer: 2

Have a good day ¯\_(ツ)_/¯
8 0
3 years ago
Read 2 more answers
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