Answer:
Step-by-step explanation:
![\frac{a^{m}}{a^{n}}=a^{m-n}\\\\a^{m}*a^{n}=a^{m+n}\\\\\frac{125t^{-4}}{5^{-3}}*625*t^{-8}\\\\=\frac{5^{3}t^{-4}}{5^{-3}}*5^{4}*t^{-8}\\\\=5^{3-[-3]+4}*t^{-4-8}\\\\=5^{3+3+4}t^{-12}\\\\=5^{10}t^{-12}\\\\=\frac{5^{10}}{t^{12}}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7Bm%7D%7D%7Ba%5E%7Bn%7D%7D%3Da%5E%7Bm-n%7D%5C%5C%5C%5Ca%5E%7Bm%7D%2Aa%5E%7Bn%7D%3Da%5E%7Bm%2Bn%7D%5C%5C%5C%5C%5Cfrac%7B125t%5E%7B-4%7D%7D%7B5%5E%7B-3%7D%7D%2A625%2At%5E%7B-8%7D%5C%5C%5C%5C%3D%5Cfrac%7B5%5E%7B3%7Dt%5E%7B-4%7D%7D%7B5%5E%7B-3%7D%7D%2A5%5E%7B4%7D%2At%5E%7B-8%7D%5C%5C%5C%5C%3D5%5E%7B3-%5B-3%5D%2B4%7D%2At%5E%7B-4-8%7D%5C%5C%5C%5C%3D5%5E%7B3%2B3%2B4%7Dt%5E%7B-12%7D%5C%5C%5C%5C%3D5%5E%7B10%7Dt%5E%7B-12%7D%5C%5C%5C%5C%3D%5Cfrac%7B5%5E%7B10%7D%7D%7Bt%5E%7B12%7D%7D)
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Answer with explanation:</h2>
Let p be the population proportion of parents who had children in grades K-12 were satisfied with the quality of education the students receive.
Given : Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of education the students receive.
Set hypothesis to test :

Sample size : n= 1055
Sample proportion : 
Critical value for 95% confidence : 
Confidence interval : 

Since , Confidence interval does not contain 0.39.
It means we reject the null hypothesis.
We conclude that 95% confidence interval represents evidence that parents' attitudes toward the quality of education have changed.
Let width be x
length= 6+x
p=2(l+w)
20=2(6+x+x)
10=2x+6
10-6=2x
4=2x
x=4/2
x=2
Therefore the width is 2 cm and length is (6+2)= 8 cm
Hope I helped :)
In order to get -140, one number has to be negative and one number has to be positive. And these two numbers when added together give you a -4, which means the greater of these numbers has to be negative.
Try guess and check strategy by listing possible factor combinations for -140 and see which one works!
Answer:
There are no like terms to therefore the answer is -4x+5y+6z