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yawa3891 [41]
3 years ago
12

How long would take you to drive around the earth at 80mph

Mathematics
1 answer:
Bess [88]3 years ago
3 0

Answer:

311.25 hours ; almost 13 days

Step-by-step explanation:

actually you will not able to drive a car all the way around the earth (the Pacific and Atlantic oceans are really big).

but According to the calculation it would take you around 311.25 hours ( almost 13 days) to drive the 24,900 miles around the circumference of the earth at its widest point (the equator).

because we know ,

t=s/v

 =(24,900/80)hours                    [ s= the circumference of the earth]

 =311.25 hours                              [v=Velocity]

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expeople1 [14]
\frac{x}{4}= \frac{5}{7}

7*x=4*5

7x=20

x=2\frac{6}{20}

x=2\frac{3}{10}

5 0
3 years ago
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A computer program randomly picks from the whole numbers 0-9 and lowercase letters, one at a time, to create a password. What is
I am Lyosha [343]
1 in 35 or <span>0.03 is the probability</span>
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3 years ago
Please help...<br> i rlly need help on this
melamori03 [73]

Answer:

3

Step-by-step explanation:

Since

3 : 2 = X : 2

Then we know

3/2 = X/2

Multiplying both sides by 2 cancels on the right

2 × (3/2) = (X/2) × 2

2 × (3/2) = X

Then solving for X

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X = 3

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5 0
3 years ago
56,426+17,895
pochemuha

Answer:

a =74,321

b. 41,042,523,288

c. 414,832,917

Step-by-step explanation:

because two odd numbers becomes a even number

5 + 5 = 10 7 + 7 = 14 etc

so in the problem you sent 13 and 15 being odd numver will result in a even number when added

8 0
3 years ago
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Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997, However in march 1997 the price of the tea increased by 25% and
Irina18 [472]

Answer: tea = 15 rupees  per kg

sugar= 3 rupees per kg

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations with the information given:

<em>"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997": </em>

2 t + 3 s =39 (a)

Where:

  • t= price of 1 kg of tea
  • s = price of 1 kg of sugar

<em>"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "</em>

2(t1.25)+3(s1.2) = 48.30 (b)

  • <em>Solving for t in (b) </em>

2t =39-3s

t = (39 -3s)/2

t = 19.5-1.5s

  • <em>Replacing the value of t in (b) </em>

2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30

2x ( 24.375 -1.875s) +3.6s =48.30

48.75 -3.75s+3.6s= 48.30

48.75-48.30 = 3.75s-3.6s

0.45= 0.15s

0.45/0.15 =s

3 =s

  • <em>Replacing the value of s in (a) </em>

2 t + 3 (3) =39

2 t + 9 =39

2 t =39 -9

2 t =30

t = 30/2

t= 15

Prices in january:

tea = 15 rupees per kg

sugar= 3 rupees per kg

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
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