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Kaylis [27]
3 years ago
6

What is 3 3/8+ 5/12=_____.Plz tell me!

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
6 0

Answer:

3 19/24

Step-by-step explanation:

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PLEASE HELPP I really need it this is a timed test
Jet001 [13]

Answer:

175 is answer

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2 years ago
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Evaluate each logarithm. Do not use a calculator. ln ^3 square root e^4
Alona [7]

Answer:

\large\boxed{\ln\sqrt[3]{e^4}=\dfrac{4}{3}}

Step-by-step explanation:

\text{Use}\\\\\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\ln a^n=n\ln a\\\\\ln e=1\\-----------\\\\\ln\sqrt[3]{e^4}=\ln e^\frac{4}{3}=\dfrac{4}{3}\ln e=\dfrac{4}{3}\cdot1=\dfrac{4}{3}

6 0
3 years ago
8. Solve for x. Round your answer to the nearest tenth.<br> 8.6<br> 4<br> x<br> 0176
earnstyle [38]

Answer:

C. 9.5

Step-by-step explanation:

The Pythagorean Theorem: a^2 + b^2 = c^2.

4^2 + 8.6^2 = c^2

16 + 73.96 = c^2

c^2 = 89.96

c = 9.4847....

8 0
3 years ago
Suppose a lawn and garden company wants to determine the current percentage of customers who use fertilizer on their lawns. How
marishachu [46]

Answer:

n=601

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.04 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have a prior estimation for the proportion we can use 0.5 as estimation. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.96})^2}=600.25  

And rounded up we have that n=601

3 0
3 years ago
The probability of drawing two red candies without replacement is 1335 , and the probability of drawing one red candy is 25 . Wh
professor190 [17]

The probability would be 50 because 25+25=50

3 0
3 years ago
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