The red chord is a diameter of the circle, so the length of the blue arc is half the circle's circumference.
The circumference of a circle with diameter is
, so the circle has circumference
, and so the arc has length
.
Which equation represents a circle with the center at (-3, -5) and a radius of 6 units?
2 answers:
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Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80
0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>From eqn 3,
d = 30 - 12
<h3>d = 18</h3>Thus she has 18 dimes and 12 quarters
Answer:
- ABCD is a rhombus, and a parallelogram
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<h3>Given </h3>- Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)
First, plot the points (see attached picture).
Then, connect all the points.
<h3>We see that:</h3>- Opposite sides are parallel,
- Diagonals are perpendicular.
From our observation the figure is rhombus.
Let's confirm it with the following.
1) Find midpoints of diagonals and compare.
- AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
- BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2
The midpoint of both diagonals is same (- 2, 2).
2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.
- m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
- m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3
- m(AC) × m(BD) = 3/4 * (- 4/3) = - 1
<u>Confirmed.</u>
So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.
Answer: Choice A
The fractions are not equivalent because the product of the numerator of the first fraction and the denominator of the second fraction is <u> 15 </u> , which is not equal to the product of the numerator of the second fraction and the denominator of the first fraction <u> 16 </u>
===================================================
Explanation:
We have the template which cross multiplies to
So if was true, then
must be true as well, and vice versa.
The left side 3*5 turns into 15, while the right hand side 4*4 becomes 16. The 15 and 16 don't match up.
In short, turns into
which is a false statement. So the original claim that
is also false.