You can rewrite that as:
a^2-4ab+6ab-24b^2 then factor 1st and 2nd pair of terms.
a(a-4b)+6b(a-4b) so you have
(a+6b)(a-4b)
I'm sorry, when I answered this I'm pretty sure I wasn't in algebra two yet. The correct answer is 4/52 * 3/51 = 1/221
Answer:
562 child tickets were sold
217 adult tickets were sold
Step-by-step explanation:
A festival charges $3 for children admission and $5 for adult admission
At the end of the festival they have sold a total number of 779 tickets for $2771
Let x represent the child ticket
Let y represent the adult ticket
x + y= 779..............equation 1
3x + 5y= 2771..........equation 2
From equation 1
x + y = 779
x= 779 -y
Substitute 779-y for x in equation 2
3x + 5y= 2771
3(779-y) + 5y= 2771
2337 - 3y + 5y= 2771
2337 +2y= 2771
2y= 2771 -2337
2y = 434
y = 434/2
y = 217
Substitute 217 for y in equation 1
x + y= 779
x + 217= 779
x = 779-217
x= 562
Hence 562 child tickets were sold and 217 adult tickets were sold
