To obtain the probability of obtaining heads at least 3 times out of 5 times we recall that in her simulation <span>she
assigned odd digits to represent heads and even digits to represent
tails. Thus, we count the simulated numbers to see in how many numbers
do we have 3 or more odd digits.
Below, the simulated numbers with 3 or more odd digits are bolded.
</span> <span>32766 53855 34591 27732
47406 31022 25144 72662
03087 35521 26658 81704
56212 72345 44019 <span>65311
</span>
We have 6 simulated numbers having 3 or more odd digits.
Therefore, </span><span>P("heads" at least 3 out of 5 times) = 6 / 16 = 3 / 8.</span>
Hey there :)
The perimeter formula of a trapezium is:
P = a + b + c + d ( adding all sides )
Perimeter is given : P = 17z³ + 60z² + 2z - 5
Part A :
Total lengths of sides 1, 2 and 3 will be just adding the given lengths :
1 → 16z² - 4z + 2
2 → 7z² - 2z + 21
3 → 18z² - 3z + 2
side 1 + side 2 + side 3
( 16z² - 4z + 2 ) + ( 7z² - 2z + 21 ) + ( 18z² - 3z + 2 )
Combine like terms together:
16z² + 7z² + 18z² - 4z - 2z - 3z + 2 +21 + 2
41z² - 9z + 25Part B:
Length of 4th side will be the total perimeter minus the total length of sides 1, 2 and 3:
( 17z³ + 60z² + 2z - 5 ) - ( 41z² - 9z + 25 )
Combine like terms
17z³ + 60z² - 41z² + 2z + 9z - 5 - 25
17z³ + 19z² + 11z - 30
Part C:
Addition of polynomials result in polynomials as well as subtraction of polynomials result in polynomials.
Therefore, this polynomial is closed under addition and subtraction.
We can draw the graph of cosine with amplitude 2.
Answer:
-2, 6, 20 ,...
Step-by-step explanation:
3n² +5n -2
if n=0 , then 3*0² +5*0 -2= -2
if n=1, then 3*1² +5*1 -2 = 3+5-2 = 6
if nu 2, then 3*2² +5*2 -2 = 12 +10 -2 = 20
Answer:
Area = 42 in^2
Step-by-step explanation:
here's your solution
=> divide above picture in two parts
=> rectangle and traingle
=> area of rectangle = length* width
=> area of rectangle = (5*6)in.
=> area of rectangle = 30 in^2
=> now, area of traingle = 1/2*base *height
=> area of traingle = 1/2*4*6
=> area of traingle = 12 in^2
=> area of figure = 30 in^2 + 12 in^2
=> Area = 42 in^2
hope it helps