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2 years ago

WILL GIVE BRAINLIEST

Mathematics

1 answer:

levacccp [35]2 years ago

5 0

Answer:

a. $5^{2} x^{3}$

b. $8^{3}$

c. $4^{3} x^{4}$

Step-by-step explanation:

a. $5^{2} x^{3}$

b. $8^{3}$

c. $4^{3} x^{4}$

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What is this can anyone help me

Solnce55 [7]

g(x) = (x - 3)² - 4

given f(x) is shifted a units horizontally to the right → f(x) → f(x - a)

If f(x) is shifted by a units horizontally left → f(x) → f(x + a)

If f(x) is shifted by b units vertically up → f(x) → f(x) + b

If f(x) is shifted by b units vertically down → f(x) → f(x) - b

The vertex (0, 0) of f(x) has shifted to (3, -4)

that is 3 units horizontally to the right and 4 units vertically down

hence g(x) = (x - 3)² - 4

4 0

3 years ago

What is the algebraic description for a transformation that translates the

MrRissso [65]

Answer:

nhgtf

Step-by-step explanation:

7 0

3 years ago

What Is the sequence of 5,10,15

Veronika [31]

Add 5
5,10,15,20,25,30....

4 0

3 years ago

The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

4 0

3 years ago

The vector ab has a magnitude of 20 units and is parallel to the<br> vector 4i + 3j.<br> find ab.

stepladder [879]

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j. Hence, The vector AB is 16i + 12j.

<h3>How to find the vector?</h3>

If we have given a vector v of initial point A and terminal point B

v = ai + bj

then the components form as;

AB = xi + yj

Here, xi and yj are the components of the vector.

Given;

The vector ab has a magnitude of 20 units and is parallel to the

vector 4i + 3j.

magnitude

$\sqrt{4^2 + 3^2} \\\\\sqrt{16 + 9} \\\\= 5$

Unit vector in direction of resultant = (4i + 3j) / 5

Vector of magnitude 20 unit in direction of the resultant

= 20 x (4i + 3j) / 5

= 4 x (4i + 3j)

= 16i + 12j

Hence, The vector AB is 16i + 12j.

Learn more about vectors;

brainly.com/question/12500691

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7 0

2 years ago