Answer:
1 x=-2.5 y = -5.5
2. x=5 y=1
Step-by-step explanation:
1) What is the solution of the given system?
5x-y=-7
3x-y=-2
Multiply the second equation by -1
-1*(3x-y)=-1(-2)
-3x +y = 2
Now add the first equation to the modified second equation
5x-y=-7
-3x +y = 2
------------------
2x = -5
Divide each side by 2
2x/2 = -5/2
x = -2.5
Now we need to find y
-3x+y =2
-3(-2.5) +y =2
7.5 +y =2
Subtract 7.5 from each side
7.5 -7.5 +y =2-7.5
y = -5.5
2) what is the solution of the given system?
5x+7y=32
8x+6y=46
Divide the second equation by 2
8x/2+6y/2=46/2
4x+3y =23
Multiply the first equation by 4
4 (5x+7y)=32*4
20x+28y = 128
Now multiply the modified 2nd equation by -5
-5(4x+3y )=-5(23
)
-20x -15y = -115
Lets add the new equations together to eliminate x
20x+28y = 128
-20x -15y = -115
---------------------
13y = 13
Divide each side by 13
13y/13 =13/13
y=1
Now substitute back in to find x
5x+7y=32
5x +7(1) =32
5x +7 =32
Subtract 7 from each side
5x+7-7 =32-7
5x =25
Divide by 5
5x/5 =25/5
x=5
Answer:
16×4= 64
64.00+3.50
(16×4)+(64.00+14.00)
Step-by-step explanation:
First you have to find how much the tickets will cost per person then add 14.00 because of the one time person but there is four so time 3.50×4
It should add up to.
x= 0.312866
Answer:
y=4x+10
Step-by-step explanation:
It's parallel so it has the same slope of 4.
Then, using slope-point formula
y-y_1=m(x-x_1)
y-6=4(x-(-1))
y-6=4x+4
y=4x+10
First question: So, we know a fence that is 3 sections long, requires 4 posts and 6 rails.
Now, we have to use this kind of fence (3 sections, 4 posts, 6 rails) to fence off a yard. The yard is rectangular, and is 6 sections long and 3 sections wide.
Since we know the fence we are using is 3 sections wide, we have to count how many of them we’ll be using for the yard.
We know all four sides of the rectangle - two sides are 3 sections long, and the other two are 6 sections long.
Our fence is 3 sections, so we can already use 2 of those for the two sides of 3 sections. We multiply the number of rails and posts by two (since we are using two of these fences) and get 8 posts and 12 rails. We’ll keep this in mind.
Now, for the other two sides: they are both 6 sections long. We know that 3+3=6, thus one of those sides would be 2 fences long, or 3 sections times 2. We have two of these 6 section sides, so we actually would be using 12 sections (6*2), or in other words, we’d use this fence 4 times (4*3). We multiply the rails and posts by 4, and get 16 posts and 24 rails.
We use the 8 posts and 12 rails from earlier and add the number of the posts and rails we got just now: 16p and 24r, and get a total of 24 posts and 36 rails.
As for the second question, even I’m having a tough time. I’ll get back to you if I can solve it.
