That would be rolling a 1 and a 2 .
so possibilities are 1 on first die and 2 on the second die
OR 2 on first die and 1 on the second.
Both of these have a probability of 1/6 * 1/6 = 1/36
so required probability = 1/36 + 1/36 = 2/36 = 1/18
6x + 2 - 2 = 14 - 2
6x/6 = 12/6
x = 2
Answer:
<u>D. He recorded his paycheck amount for April 23rd incorrectly. Yes, this was Adam's mistake. The correct amount should be 341.60 and not 338.45.</u>
Step-by-step explanation:
1. Let's review the information given to us to help Adam to determine where his error is.
A. He completely forgot to include the clothes he bought from Bargains RUS. No, he didn't. It was recorded properly, including the sales tax amount.
B. He made an arithmetic error in the balance column. No he didn't, the balance was calculated correctly after each transaction.
C. He recorded one of his withdrawals in the deposit column. No, he didn't. All of the withdrawals are in the right column.
<u>D. He recorded his paycheck amount for April 23rd incorrectly. Yes, this was Adam's mistake. The correct amount should be 341.60 and not 338.45.</u>
Answer:
Hello,
in order to simplify, i have taken the inverses functions
Step-by-step explanation:
![\int\limits^\frac{1}{2} _{-1} {(-2x^2-x+1)} \, dx \\\\=[\frac{-2x^3}{3} -\frac{x^2}{2} +x]^\frac{1}{2} _{-1}\\\\\\=\dfrac{-2-3+12}{24} -\dfrac{-5}{6} \\\\\boxed{=\dfrac{9}{8} =1.25}\\](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%5Cfrac%7B1%7D%7B2%7D%20_%7B-1%7D%20%7B%28-2x%5E2-x%2B1%29%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5B%5Cfrac%7B-2x%5E3%7D%7B3%7D%20-%5Cfrac%7Bx%5E2%7D%7B2%7D%20%2Bx%5D%5E%5Cfrac%7B1%7D%7B2%7D%20_%7B-1%7D%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B-2-3%2B12%7D%7B24%7D%20-%5Cdfrac%7B-5%7D%7B6%7D%20%5C%5C%5C%5C%5Cboxed%7B%3D%5Cdfrac%7B9%7D%7B8%7D%20%3D1.25%7D%5C%5C)
