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3 years ago

State the degree and leading coefficient of each polynomial in one variable. If it is not a polynomial in one variable, explain

why.
Need help

1. −6x^6−4x^5+13yx

2. 8x^5 -12x^6+14x^3-9

3. 15x-4x^3+3x^3-5x^4

4. (d + 5)(3d -4)

5. 6x^5 - 5x^4+2x^9-3x^2

Mathematics

1 answer:

musickatia [10]3 years ago

3 0

$1.\\-6x^6-4x^5+13xy\\degree:6\\it's\ not\ a\ polynominal\ in\ one\ variable\ (13x\boxed{y})\\\\2.\\8x^5-12x^6+14x^4-9\\degree:5\\leading\ coefficient:8\\\\3.\\15x+4x^3+3x^3-5x^4\\degree:4\\leading\ coefficient:-5$

$4.\\(d+5)(3d-4)=3d^2-4d+15d-20\\degree:2\\leading\ coefficient:3\\\\5.\\6x^5-5x^4+2x^9-3x^2\\degree:9\\leading\ coefficient:2$

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Answer:

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Step-by-step explanation:

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0 = A+B

0 = 1+B

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<u>step 3:-</u>

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

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Option C is correct

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