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pantera1 [17]
3 years ago
10

State the degree and leading coefficient of each polynomial in one variable. If it is not a polynomial in one variable, explain

why.
Need help

1. −6x^6−4x^5+13yx

2. 8x^5 -12x^6+14x^3-9

3. 15x-4x^3+3x^3-5x^4

4. (d + 5)(3d -4)

5. 6x^5 - 5x^4+2x^9-3x^2

Mathematics
1 answer:
musickatia [10]3 years ago
3 0
1.\\-6x^6-4x^5+13xy\\degree:6\\it's\ not\ a\ polynominal\ in\ one\ variable\ (13x\boxed{y})\\\\2.\\8x^5-12x^6+14x^4-9\\degree:5\\leading\ coefficient:8\\\\3.\\15x+4x^3+3x^3-5x^4\\degree:4\\leading\ coefficient:-5

4.\\(d+5)(3d-4)=3d^2-4d+15d-20\\degree:2\\leading\ coefficient:3\\\\5.\\6x^5-5x^4+2x^9-3x^2\\degree:9\\leading\ coefficient:2

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Ice has a density of 0.92 g/cm3. What is the volume of 100 grams of ice? If the ice completely melted, what would the volume of
kicyunya [14]

Hello!

To find the volume of the water, we would need to use the density formula. The density formula is d = m/V.

In this formula, d is the density, m is the mass and V is the volume.

1. To find the volume of 100 grams of ice, we substitute the appropriate values into the formula and solve for the volume using basic algebra.

0.92g/cm³ = 100g/V (multiply both sides by V)

0.92g/cm³ · V = 100g (divide both sides by 0.92g/cm³)

V = 108.69 cm³.

The volume of 100 grams of ice is about 108.69 cm³.

2. To find the volume of the completely melted ice, we would use the same formula, but the density is now 1.00 g/mL.

1.00g/mL = 100g/V (multiply both sides by V)

1.00g/mL · V = 100g (divide both sides by 1.00g/mL)

V = 100 mL

Therefore, the volume of the melted ice is 100 mL.

<u>Final answers</u>:

  1. 108.69 g/cm³
  2. 100 mL
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Solve the following inequality: –1 + 6(–1 – 3x) &gt; –39 – 2x.    
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<span>–1 + 6(–1 – 3x) > –39 – 2x. 
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What’s the answer to this please? Thanks!
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Answer:

70

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