Question

The dipole moment of the water molecule (H2O) is 6.17x10^-30 C.m. Consider a water molecule located at the origin whose dipole moment p points in the +x-direction. A chlorine ion (Cl-), of charge-1.60x10^-19C , is located at x=3.00x10^-9m . Assume that is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis can be used.
A) Find the magnitude of the electric force that the water molecule exerts on the chlorine ion.

Answer 1

Answer:

There are other details missing in the question. i.e Assume that x is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis E = p/2πε0y3 can be used, where p is the dipole moment, and y is the distance between ions. A) What is magnitude______N B) Direction? +x-direction or -x-direction C) Is this force attractive or repulsive?

A) Magnitude of electric force = 6.576 x 10 raised to power -13 N

B) Since the force direction is always dependent on the electric field and electric field = F/q, since the chlorine has a negative charge as such the direction of the electric force will be in the X - direction

C) Since the charges are of different nature, as such the force between them will be ATTRACTIVE.

Explanation:

The detailed steps is shown in the attachment