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MaRussiya [10]
3 years ago
10

The dipole moment of the water molecule (H2O) is 6.17x10^-30 C.m. Consider a water molecule located at the origin whose dipole m

oment p points in the +x-direction. A chlorine ion (Cl-), of charge-1.60x10^-19C , is located at x=3.00x10^-9m . Assume that is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis can be used.
A) Find the magnitude of the electric force that the water molecule exerts on the chlorine ion.

Chemistry
1 answer:
valkas [14]3 years ago
8 0

Answer:

There are other details missing in the question. i.e Assume that x is much larger than the separation d between the charges in the dipole, so that the approximate expression for the electric field along the dipole axis E = p/2πε0y3 can be used, where p is the dipole moment, and y is the distance between ions. A) What is magnitude______N B) Direction? +x-direction or -x-direction C) Is this force attractive or repulsive?

A) Magnitude of electric force = 6.576 x 10 raised to power -13 N

B) Since the force direction is always dependent on the electric field and electric field = F/q, since the chlorine has a negative charge as such the direction of the electric force will be in the X - direction

C) Since the charges are of different nature, as such the force between them will be ATTRACTIVE.

Explanation:

The detailed steps is shown in the attachment

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If one or more nucleotide pairs are deleted from a dna strand, this is known as a:_________
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If one or more nucleotide pairs are deleted from a DNA strand, this is known as a frameshift mutation

<h3>Define Frameshift Mutation</h3>

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One of the most harmful modifications to a protein's coding sequence is a frameshift mutation. They are quite prone to produce non-functional proteins that frequently interfere with a cell's metabolic processes and result in significant alterations to polypeptide length and chemical makeup. Frameshift mutations can cause the mRNA to stop translating too soon and create an extended polypeptide.

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4 0
1 year ago
C12H26O + SO3+NaOH ----&gt; C12H25NaSO4+ H2O
Vlad [161]

Answer:

We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

so to get one mole of C12H25NaSO4 we need one mole of C12H26O

so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O

so the mass of C12H26O = 41.26× its molar mass

C12H26O = 41.26×186.34

= 7688.38 gm!!

so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!

Again i d k wether it's right or wrong but i tried my best hope it helped you!!

4 0
3 years ago
Given the chemical equation: 2 Pb + O2 → 2 PbO, if 51.8 grams of Pb are formed in this reaction, then 8.00 grams of O2 must have
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Answer:

If 51.8 of Pb is reacting, it will require 4.00 g of O2

If 51.8 g of PbO is formed, it will require 3.47 g of O2.

Explanation:

Equation of the reaction:

2 Pb + O2 → 2 PbO

From the equation of reaction, 2 moles of lead metal, Pb, reacts with 1 mole of oxygen gas, O2, to produce 2 moles of lead (ii) oxide, PbO

Molar mass of Pb = 207 g

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Therefore 2 × 207 g of Pb reacts with 32 g of O2 to produce 2 × 239 g of PbO

= 414 g of Pb reacts with 32 g of O2 to produce 478 g of PbO

Therefore, formation of 51.8 g of PbO will require (32/478) × 51.8 of O2 = 3.47 g of O2.

If 51.8 of Pb is reacting, it will require (32/414) × 51.8 g of O2 = 4.00 g of O2

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grigory [225]

Answer:

im not sure

Explanation:

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