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asambeis [7]
3 years ago
5

What is the product(s) in the reaction below?

Chemistry
2 answers:
mixas84 [53]3 years ago
6 0

Answer:

imma go with the answer B

Thepotemich [5.8K]3 years ago
3 0

Answer:

it's D.) Zncl2 (aq) + H2 (g)

Explanation:

because product is written in Right hand side (RHS) Of a reaction after the arrow sign.

oh okay

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As the atomic number increases, the number of _ _, too.
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Answer:

Protons

Explanation:

The atomic number represents the number of protons. Therefore, as the atomic number increases, the number of protons does too.

I hope this helps! :)

8 0
3 years ago
Read 2 more answers
7. Explain how magnetic potential energy can be transformed into kinetic energy. (1<br> point)
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2 years ago
How should you remove a beaker from a hot plate after heating it?.
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Answer:

Explanation:

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2 years ago
Will the ph of a solution of nh4cn be &gt;7, &lt;7, or =7?
never [62]
PH of a solution will be <span>higher than 7
</span>
Ammonium cyanide is a salt formed by hydrogen cyanide and ammonia. Ammonia is a weak base and hydrogen cyanide is a weak acid. 
NH₄CN + H₂O ⇒ NH₃ + HCN 

NH₄⁺ + H₂O -----> H₃O⁺ + NH₃

CN⁻ + H₂O -----> HCN + OH⁻ 

Although both compounds are weak electrolytes, NH₃ is somewhat stronger base than HCN is a strong acid, so the solution reacts alkaline. We can prove this using Ka and Kb values:

Ka(HCN) = 4.9 x × 10⁻¹⁰

Kb(NH₃) = 1.8 × 10⁻⁵<span>
Kw= </span>1.0 × 10⁻¹⁴

Let's first calculate Ka for NH₄⁺: 
Ka(NH₄⁺) x Kb(NH₃<span>) = pKw

</span>Ka(NH₄⁺) = Kw/Kb(NH₃) = 5.6 x 10⁻¹⁰

Then, Kb for CN⁻:

Kb(CN⁻) x Ka(HCN) = pKw

Kb(CN⁻) = Kw/Ka(HCN) = 2 x 10⁻⁵

 
From this, we can see that the acid constant NH4⁺ is much lower than the base constant of CN⁻, which will say that the solution of NH₄CN will react slightly alkaline because of the higher presence of hydroxyl ions in solution.


7 0
3 years ago
How much heat, in calories, is given off when 1.25 grams of silver is cooled from 100.0 degrees Celsius to 80 degrees Celsius? (
lapo4ka [179]
The heat required to raise the temperature of a certain mass of sample to a specific temperature change, we use the formula mCpΔT where m is mass, Cp is the specific heat of the substance and ΔT is the temperature change. In this case, we substitute and form 1.25 g x 0.057 cal/g C *20 C equal to 1.425 calories.
7 0
3 years ago
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