All categories

3 years ago

Calculate the number of moles found in 3.045x1024 atoms of helium. PLS HELP

Chemistry

1 answer:

Kisachek [45]3 years ago

4 0

Explanation:

so for this u have to use this equation where

Moles = number of particle/6.02×10^23

= 3.045 × 10^24/6.02×10^23

= 5.0581

write it to 3 S.F so 5.06 moles

You might be interested in

(10 points) Please help asap!!

icang [17]

Answer:

1-3 2-2 3-1

Explanation:

7 0

4 years ago

What is the frequency of a wave of intrared light which has a wavelength of 4.35 * 10 ^ - 5 meters?

weqwewe [10]

Answer

6.9 x 10¹²Hz

Explanation:

Given parameters:

Wavelength of the wave = 4.35 x 10⁻⁵m

Unknown:

Frequency of the wave = ?

Solution:

The speed of a wave is related to the wavelength and frequency using the expression below;

C = Fλ

C is the speed of light = 3 x 10⁸m/s

F is the frequency

λ is the wavelength

Insert the given parameters and solve;

3 x 10⁸ = F x 4.35 x 10⁻⁵

F = $\frac{3 x 10^{8} }{4.35 x 10^{-5} }$ = 6.9 x 10¹²Hz

6 0

3 years ago

Emprical formula for c6h6

Vesna [10]

The emperical formula for benzene (C6H6) is “CH”.

7 0

3 years ago

How many grams of o2 are necessary to react with 212 G of mg 2mg+o2➡2mgo?

gulaghasi [49]

We are given an equation 2Mg+O2-> 2MgO and a starting chemical Mg of about 212 g. In order to solve for the amount of O2 needed, we need the molecular weight of Mg and O2.
Molecular weight:
Mg=24.305 g/mol
O2=16(2)=32 g/mol

Note that for every 1 mol of O2, the amount of Mg must be 2 mol.
So,
g O2 = 212 g Mg x1mo Mgl/24.305 g Mg x1mol O2 /2 mol Mg x 32 g O2/mol O2

gO2=139.56 g

Therefore, 139.56 g of O2 is needed for every 212 g Mg.

7 0

4 years ago

Give the number of significant figures: 0.011 cm<br><br> Significant figures:

Elodia [21]

There are 2 significant figures

3 0

3 years ago

Read 2 more answers