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MissTica
3 years ago
6

Calculate the number of moles found in 3.045x1024 atoms of helium. PLS HELP

Chemistry
1 answer:
Kisachek [45]3 years ago
4 0

Explanation:

so for this u have to use this equation where

Moles = number of particle/6.02×10^23

= 3.045 × 10^24/6.02×10^23

= 5.0581

write it to 3 S.F so 5.06 moles

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5.1169 mol of Ne is held at 0.9148 atm and 911 K. What is the volume of its container in liters?
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By applying the Boyle's equation and substituting our given data the volume of the container was found to be 418.14 Litres

<h3>Boyle's  Law</h3>

Given Data

  • number of moles of Ne = 5.1169 mol
  • Pressure = 0.9148 atm
  • Temperature = 911 K

We know that the relationship between pressure and temperature is given as

PV = nRT

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brainly.com/question/469270

5 0
2 years ago
How many moles are in 325mL of 1.25M (NH4)2SO4
mote1985 [20]

Answer:

n_{solute}=0.406mol(NH_4)_2SO_4

Explanation:

Hello,

In this case, since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:

M=\frac{n_{solute}}{V_{solution}}

For the given volume and molarity, we solve for the moles of ammonium sulfate (solute) as shown below:

n_{solute}=M*V_{solution}=1.25\frac{mol}{L}*325mL*\frac{1L}{1000mL}  \\\\n_{solute}=0.406mol(NH_4)_2SO_4

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