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MissTica
2 years ago
6

Calculate the number of moles found in 3.045x1024 atoms of helium. PLS HELP

Chemistry
1 answer:
Kisachek [45]2 years ago
4 0

Explanation:

so for this u have to use this equation where

Moles = number of particle/6.02×10^23

= 3.045 × 10^24/6.02×10^23

= 5.0581

write it to 3 S.F so 5.06 moles

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Katena32 [7]
H2So4 is a strong acid and a strong electrolyte which means that when this dissociates in water, the dissociation process is complete. The first dissociation is 

H2 SO4 = H + HSO4- 

This can further release H+ and dissociate SO4- instead already
4 0
3 years ago
Consider the nuclear equation below. 239/94 Pu—-> X+ 4/2 He. What is X?
Anna007 [38]

Answer:

X = U (Uranium)

Explanation:

Pu-->235/92 U + 4/2 He

4 0
2 years ago
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If 25.3 grams of mercury(II) oxide react to form 23.4 grams of mercury, how many grams of oxygen must simultaneously be formed?
sergij07 [2.7K]

Answer : The mass of oxygen formed must be 3.8 grams.

Explanation :

Law of conservation of mass : It states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The balanced chemical reaction will be,

2HgO\rightarrow 2Hg+O_2

According to the law of conservation of mass,

Total mass of reactant side = Total mass of product side

Total mass of 2HgO = Total mass of 2Hg+O_2

As we are given :

The mass of HgO = 25.3 grams

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So,

2\times 25.3g=2\times 23.4g+\text{Mass of }O_2

50.6g=46.8g+\text{Mass of }O_2

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Therefore, the mass of oxygen formed must be 3.8 grams.

6 0
3 years ago
Which laws can be combined to form the ideal gas law?
ahrayia [7]
Answer: Charles's law, Avogadro's law andd Boyle's law.

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So, all those three laws combined state the relation of pressure, volume, temperature and number of particles of a gas, which is what the ideal gas law does: PV = n RT.
4 0
3 years ago
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(Please Help)
Marianna [84]

Answer:

B

Explanation:

Trust me I've had problems like these

6 0
2 years ago
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