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2 years ago

Please help me. Should I know this?

1 answer:

7 0

you don't need to know this for real life situations but for school you do need to know it, i dont know how to do this but here's a link to the same question you have but it's explained on how to solve it

https://www.wyzant.com/resources/answers/499729/fireworks_can_go_up_to_1000_feet_in_around_3_seconds_what_s_is_it_s_average_vertical_speed_in_feet_per_second_and_miles_per_hour

((Also i'm a fellow ARMY as well =) ))

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7(2p+3)-8=6p+29 Please some help me solve this equation with steps.

stepan [7]

So,

First, I'd like to note that it is required to show work. You shouldn't need to ask for steps.

7(2p + 3) - 8 = 6p + 29

Distribute
14p + 21 - 8 = 6p + 29

Collect Like Terms
14p + 13 = 6p + 29

Subtract 6p from both sides
8p + 13 = 29

Subtract 13 from both sides
8p = 16

Divide both sides by 8
p = 2

Check
7(2(2) + 3) - 8 = 6(2) + 29

Simplify inside the parentheses first.
7(4 + 3) - 8 = 6(2) + 29
7(7) - 8 = 6(2) + 29

Now, distribute.
49 - 8 = 12 + 29

Collect Like Terms
41 = 41 This checks.

S = { 2 }

4 0

2 years ago

Read 2 more answers

15q - 12 = 18 help me pls

Jet001 [13]

The answer is q=15

Hope this helps ya

8 0

2 years ago

What is the value of this expression when n approaches infinity?

topjm [15]

ANSWER

C. 35

EXPLANATION

The given expression is:

$15 - 35 - \frac{85}{n} + 55 + \frac{75}{2n} + \frac{15}{2 {n}^{2} }$

$n \to \: \infty$

$\frac{k}{n} \to0$

where k is a constant.

This implies that,

$15 - 35 - \frac{85}{n} + 55 + \frac{75}{2n} + \frac{15}{2 {n}^{2} } = 15 - 35 - 0 + 55 + 0+ 0 =35$

The correct answer is C

4 0

3 years ago

Read 2 more answers

Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

GarryVolchara [31]

Question 6

1) $\overline{AB} \cong \overline{BD}$ , $\overline{CD} \perp \overline{BD}$ , O is the midpoint of $\overline{BD}$ , $\overline{AB} \cong \overline{CD}$ (given)

2) $\angle ABO, \angle ODC$ are right angles (perpendicular lines form right angles)

3) $\triangle ABO, \triangle CDO$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{BO} \cong \overline{OD}$ (a midpoint splits a segment into two congruent parts)

5) $\triangle ABO \cong \triangle CDO$ (LL)

Question 7

1) $\angle ADC, \angle BDC$ are right angles), $\overline{AD} \cong \overline{BD}$

2) $\overline{CD} \cong \overline{CD}$ (reflexive property)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\triangle ADC \cong \triangle BDC$ (LL)

5) $\overline{AC} \cong \overline{BC}$ (CPCTC)

Question 8

1) $\overline{CD} \perp \overline{AB}$ , point D bisects $\overline{AB}$ (given)

2) $\angle CDA, \angle CDB$ are right angles (perpendicular lines form right angles)

3) $\triangle CDA, \triangle CDB$ are right triangles (a triangle with a right angle is a right triangle)

4) $\overline{AD} \cong \overline{DB}$ (definition of a bisector)

5) $\overline{CD} \cong \overline{CD}$ (reflexive property)

6) $\triangle ADC \cong \triangle BDC$ (LL)

7) $\angle ACD \cong \angle BCD$ (CPCTC)

8 0

1 year ago

Hey 64° angle is bisected buy a really what is the measure of each angle formed

Oliga [24]

So it would be 64÷2=32
since if it is bisected it is cut in half which would result in each of the two angles being 32 degrees

7 0

2 years ago