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3 years ago

How is the Expanded Notation Method used for 82 times 3

Mathematics

2 answers:

MaRussiya [10]3 years ago

7 0

80X3 PLUS 2x3 that is awnser

Contact [7]3 years ago

4 0

Try looking it up c: or 80x3=[8x3=24)+0so that will be 240 and x 2 so 24x2=48+0 so it will be 480

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There are approximately 3.2 x 10^7 mosquitoes near each backyard pool. How many total mosquitoes are thre in a city with 6.7 x 1

dexar [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

There are approximately $3.2 \times 10^7$ mosquitoes near each backyard pool.

The city has total number of pools $6.7 \times 10^{12}$ .

So the total mosquitoes will be : $3.2 \times10^7 \times6.7\times 10^{12}$

So the total mosquitoes will be : $21.44 \times 10^{19}$

So the total mosquitoes will be : $2.144 \times 10^{20}$ : Answer

Hope it will help :)

3 0

2 years ago

If 2x- 3 + 3x = 28 what is the value of x

andreev551 [17]

Answer:

x= 31/5 (Exact form)

x= 6.2 (Decimal Form)

x= 6 1/5 (Mixed number form)

Step-by-step explanation:

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3 years ago

THIS IS FOR STATISTICS (PAIRED T-TEST)

AleksandrR [38]

Answer:

Oh Ana significa familia

Step-by-step explanation:

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2 years ago

Please help with Math :) Thanks!

algol [13]

Last choice the area becomes 25 times greater

6 0

2 years ago

Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x

egoroff_w [7]

Answer:

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

Determine the slope (m):

$y = 1 -2x$

Rearrange into slope-intercept form:

$y = -2x+1$

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of $\displaystyle\frac{1}{2}$ . Plug this into $y=mx+b$ :

$y=\displaystyle\frac{1}{2} x+b$

Determine the y-intercept (b):

$y=\displaystyle\frac{1}{2} x+b$

Plug in the given point (1,3) and solve for b:

$3=\displaystyle\frac{1}{2} *1+b\\\\b=\displaystyle \frac{5}{2}$

Therefore, the y-intercept is $\displaystyle \frac{5}{2}$ . Plug this back into $y=\displaystyle\frac{1}{2} x+b$ :

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

I hope this helps!

8 0

2 years ago