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Lerok [7]
3 years ago
10

Which of the following is equivalent to (x^4/3 x^2/3)^1/3

Mathematics
2 answers:
Reika [66]3 years ago
7 0

Answer:

The answer is2nd point

Step-by-step explanation:

{n}^{a}  \times  {n}^{b}  =  {n}^{a + b}

(x^4/3)×(x^2/3) = x^(4/3 + 2/3)

= x²

{( {n}^{a} )}^{b}  =  {n}^{ab}

(x²)^1/3 = x^(2×1/3)

= x^2/3

podryga [215]3 years ago
4 0

Answer:

x^2^/^3

Step-by-step explanation:

=(x^4^/^3 x^2^/^3)^1^/^3

as

a^1 . a^1 = a^1^+^1

=(x^2)^1^/^3

=x^2^/^3^

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What I don’t get it
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Y=-1/2x +7
yarga [219]

Answer:

B; (2,-4)

Step-by-step explanation:

The general equation of a straight line is;

y = mx + b

where m is the slope and b is the y-intercept

So from the question, when we look at the given equation, its slope is -1/2

mathematically, when two lines are perpendicular, the product of their slopes is -1

thus;

m1 * m2 = -1

m2 * -1/2 = -1

-m2 = -2

m2 = 2

The general equation form is;

y-y1 = m(x-x1)

where (x1,y1) = (4,0)

y-0 = 2(x-4)

y = 2x - 8

So, now we look at the point that will work for this equation

For the line that will work, if we substitute its x-value, we get the y-value

Let us take a look at option B

y = 2(2) -8 = 4-8 = -4

we can see that (2,-4) works

4 0
3 years ago
At a grocery​ store, you want to buy 3 3/5 lb of . What decimal should the digital scale​ show?
nasty-shy [4]

Answer:

3.6 lb

Step-by-step explanation:

to find the decimal of a fraction, you simply divide the numerator by the denominator. 3 divided by 5 equals 0.6, which is added to the end of your whole number.

4 0
3 years ago
Which set of ordered pairs represents a function? {(-2, 4), (-1, 6), (-6, 3), (-6, 4)} {(5, 5), (9, 5), (-8, 0), (-7, 8)} {(-2,
Mademuasel [1]

The first set. It repeated 6 on the X value

5 0
3 years ago
What types of numbers are undefined when they are under a radical sign? If you were dealing with the number √-1, would it be def
Misha Larkins [42]
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1

If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1

If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)

If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)

however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1

If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1

and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
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Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
8 0
3 years ago
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