Answer:
B; (2,-4)
Step-by-step explanation:
The general equation of a straight line is;
y = mx + b
where m is the slope and b is the y-intercept
So from the question, when we look at the given equation, its slope is -1/2
mathematically, when two lines are perpendicular, the product of their slopes is -1
thus;
m1 * m2 = -1
m2 * -1/2 = -1
-m2 = -2
m2 = 2
The general equation form is;
y-y1 = m(x-x1)
where (x1,y1) = (4,0)
y-0 = 2(x-4)
y = 2x - 8
So, now we look at the point that will work for this equation
For the line that will work, if we substitute its x-value, we get the y-value
Let us take a look at option B
y = 2(2) -8 = 4-8 = -4
we can see that (2,-4) works
Answer:
3.6 lb
Step-by-step explanation:
to find the decimal of a fraction, you simply divide the numerator by the denominator. 3 divided by 5 equals 0.6, which is added to the end of your whole number.
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.