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vodka [1.7K]
3 years ago
7

a line that contains point (2, –2) and perpendicular to another line whose slope is –1. What is the equation of the line and gra

ph?
Mathematics
1 answer:
dolphi86 [110]3 years ago
5 0
It would x - 4 = y because tge opposite reciprocal of -1 is 1 and so using point slope form y + 2 = x - 2 and when simplified youll get x - 4 = y.
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The value of 30, to one decimal place, is approximately what?​
andrew-mc [135]

the answer is 5.5

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so we can round this off to one decimal point

and when we do the final answer will be 5.5

<em>hope</em><em> </em><em>that</em><em> </em><em>helps</em><em> </em><em>!</em>

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3 years ago
Write the following number in standard decimal form.<br> one and eighty-five hundredths
sergejj [24]

Answer:

1.85

Step-by-step explanation:

0ne (1) and Eighty - five hundredths (0.85)

Hope this helps

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The dwarves of the Grey Mountains wish to conduct a survey of their pick-axes in order to construct a 99% confidence interval ab
Dmitry_Shevchenko [17]

Answer:

The minimum sample size needed is 125.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

\pi = 0.25

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

What minimum sample size would be necessary in order ensure a margin of error of 10 percentage points (or less) if they use the prior estimate that 25 percent of the pick-axes are in need of repair?

This minimum sample size is n.

n is found when M = 0.1

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.1 = 2.575\sqrt{\frac{0.25*0.75}{n}}

0.1\sqrt{n} = 2.575{0.25*0.75}

\sqrt{n} = \frac{2.575{0.25*0.75}}{0.1}

(\sqrt{n})^{2} = (\frac{2.575{0.25*0.75}}{0.1})^{2}

n = 124.32

Rounding up

The minimum sample size needed is 125.

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