12t (that's the $12 for a shirt) + 25s (25 dollars for shorts) < (or equal too) 126
The combination cost for the shirts and shorts has to be less than or equal to $126
t + s > (or equal too) 5
The total number of items has to be greater then or equal too or equal to 5
The answer would be 9 87/100
Answer:
-9, -5, -4.1, -4
Step-by-step explanation:
I think what you're missing here is that there is a negative sign in front of the q. This means that whatever number you put in for q will be multiplied by negative 1. Positive numbers will become negative, and negative numbers will become positive.
If you substitute 9 for q you will get 
, which is clearly not true, because -9 is way less than 4.
For writing the equation you divide both sides by -1. When you do this however, you must flip the inequality sign
the > sign turned into <, and the q and 4 switched signs.
The answer is 468 because 9×52 is 468
Answer:
- A -- base 3, height 4
- B -- base 4, height 4
- C -- base 3, height 3
- D -- base 3, height 5
Step-by-step explanation:
A sort of straightforward way to approach this is to define base and height variables for each of the figures: ba, ha, bb, hb, bc, hc, bd, hd. Then the statements can be used to make equations in these variables.
0. hc = bc . . . . figure C is a square
1. ba = bd
2. ba = bb -1
3. hc = ba
4. hb = ha = bb
5. hc·bc = 9
6. (1/2)ha·ba +(1/2)hb·bb +hc·bc+hd·bd = 38
__
Using equations 0 and 5, we find ...
hc² = 9 ⇒ hc = 3
From equation 3, ...
ba = 3
From equation 2, ...
3 = bb -1 ⇒ bb = 4
From equation 1, ...
bd = 3
From equation 4, ...
ha = hb = 4
Filling in the values we know in equation 6, we get ...
(1/2)(4)(3) +(1/2)(4)(4) +9 +hd(3) = 38
23 +3hd = 38
hd = 15/3 = 5
The dimensions are:
- A -- base 3, height 4
- B -- base 4, height 4
- C -- base 3, height 3
- D -- base 3, height 5
