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RideAnS [48]
3 years ago
6

What would x^4-10x^2+25 be equivalent to

Mathematics
1 answer:
Mademuasel [1]3 years ago
7 0

Answer:

if i can get brainliest that would be great

IF Factor x4−10x2+25

x4−10x2+25

=(x2−5)(x2−5)

Answer:

(x2−5)(x2−5)

IF simplify

x4−10x2+25

There are no like terms.

Answer:

=x4−10x2+25

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1,665.25 km

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I nee<br> d help on my fractions!!
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The table represents a function.
yan [13]

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The table represents a function.

What is the value of f(-1)?

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2 years ago
How to construct a triangle with side lengths 10 cm and 14 cm and an angle between them of 60 degrees.
Yuliya22 [10]

Answer:

We draw line AB which is perpendicular to the 14 cm side

Since Angle C is 60 degrees that makes angle CAB = 30 degrees

Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm

Line BD equals 9 cm

Line AB^2 = 10^2 - 5^2 = 75

Line AD^2 = AB^2 + BD^2

Line AD^2 = 75 + 81

Line AD^2 = 156

Line AD = 12.4899959968

Line AB = Sqr root (75) = 8.6602540378

Angle D = arc sine  (8.6602540378 / 12.4899959968)

Angle D = 43.898 degrees

Angle A = 180 - 60 - 43.898 = 76.102 degrees

*****************************************************************

Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.

Step-by-step explanation:

4 0
3 years ago
A packaging company is planning is in the planning stages of creating a box that include a three dimensional support inside the
Oliga [24]

Answer:

The length of the diagonal support is 69 feet.

Step-by-step explanation:

Dimensions of the box: length = 6 feet

                                       width = 5 feet

                                       height = 8 feet

The diagonal support relates with the diagonal of the base and the height.

From the base of the box, let the length of its diagonal be represented by x. Applying Pythagoras theorem;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

x^{2} = 6^{2} + 5^{2}

x^{2} = 36 + 25

   = 61

x = \sqrt{61}

  = 7.81

let the length of the diagonal support be represented by l. So that;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

l^{2} = x^{2} + 8^{2}

  = \sqrt{61} + 64

l  = \sqrt{\sqrt{61} + 64 }

  = 61 + 8

  = 69

Thus, the length of the diagonal support is 69 feet.

6 0
3 years ago
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