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Dominik [7]
3 years ago
10

Whats between 0.4 and 0.5

Mathematics
2 answers:
crimeas [40]3 years ago
8 0
There are <em>infinitely many </em>numbers between 0.4 and 0.5, but I'd imagine what you're asking is "what number is <em>halfway between</em> 0.4 and 0.5?"

Remember that <em>trailing zeroes</em> (the zeroes after the end of a decimal fraction) don't alter the number itself, so we can also write 0.4 and 0.5 as 0.40 and 0.50, 40 hundredths and 50 hundredths. Since 45 is halfway between 40 and 50, it makes sense that 45 <em>hundredths - </em>0.45 in decimal form -<em> </em>is halfway between 40 and 50 <em>hundredths</em>.
nirvana33 [79]3 years ago
3 0
0.45 since it’s

0.41 0.42 0.43 0.44 0.45 0.46 0.47 0.48 0.49
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Answer:

The total money spend on total tax of purchase is $4.625

Step-by-step explanation:

Given as :

The percentage of sales tax applied on gasoline purchase = 8.5%

The percentage of excise tax applied on gasoline purchase = 10%

The price of gasoline before tax = $25

Let The total money on total tax of purchase = $x

Now, Total percentage of tax = sales tax percentage + excise tax percentage

i.e  Total percentage of tax = 8.5% + 10%

Or,  Total percentage of tax = 18.5%

<u>Again</u>

total money on total tax of purchase = $25 of total total tax percentage

Or, x = $25 × 18.5%

Or, x = $25 × \dfrac{18.5}{100}

Or, x = $25 × 0.185

∴  x = $4.625

So,The total money on total tax of purchase = x = $4.625

Hence,The total money spend on total tax of purchase is $4.625 Answer

4 0
2 years ago
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Step-by-step explanation:

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10 times as many as _ hundreds is 60 hundreds or _ thousands
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6 0
3 years ago
Which of these limits evaluate to 0?
Vikentia [17]
<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\

----------

Part II

\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\

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Part III

\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\

7 0
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