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3 years ago

How do i determine the value of sine

Mathematics

2 answers:

Ksivusya [100]3 years ago

7 0

Sin = opposite over hypotenuse

Margaret [11]3 years ago

4 0

Well, you can do that by many ways like:
If you have value of B & P or B & H, you can find the other one by the formula,
H² = P²+B²
Then, you can easily calculate the value of sine by putting P/H

Hope this helps!

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Three angles of a quadrilateral are 75,120, 90,then the fourth angle..

Roman55 [17]

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Geometry

Sum of Angles in a Quadrilateral: 360

Step-by-step explanation:

Step 1: Set up

75 + 120 + 90 + ∠4 = 360

Step 2: Solve

Add: 285 + ∠4 = 360
[Subtraction Property of Equality] Subtract 285 on both sides: ∠4 = 75

5 0

3 years ago

If k(1) = 7' and p(x) = k (2) + n, what is the value of n?

ioda

Answer:

N=p(x)-14

As you didnt gave value of x so i Didnt got constant value

6 0

3 years ago

Please help !Suppose that the height in centimeters of a candle is a linear function of them out of time in hours it has been bu

Elan Coil [88]

Answer:

17.8 cm

Step-by-step explanation:

In the 17 hours between heights of 18.6 cm and 15.2 cm, the candle lost 3.4 cm in height. That is, the height decreased at the rate of ...

(-3.4 cm)/(17 h) = -0.2 cm/h

In the 4 hours between 12 hours and 16 hours of burning time, the candle will have changed its height by (4 h)(-0.2 cm/h) = -0.8 cm.

The height at 16 hours of burning is then 18.6 cm -0.8 cm = 17.8 cm.

4 0

3 years ago

Which is greater 78.61 or78.6

ANTONII [103]

Answer:

78.61 is greater than 78.6.

Step-by-step explanation:

Adding a zero to 78.6, resulting in 78.60, makes it easier to compare 78.6 and 78.61. 78.61 is greater than 78.6.

7 0

3 years ago

The perimeter of a rectangle is 42 inches, and its area is 110 square inches. find the length and width of the rectangle.

lorasvet [3.4K]

$p = 2w + 2l$ $p = 42$
$a = l * w$ $a = 108$

You want to make either the length or width variable (I chose the width variable to be by itself. It doesn't matter) by itself by:

Divide both sides by 2.
(p) ÷ 2 = (2w + 2l) ÷ 2
$2's$ $cancel$ $out$
$\frac{p}{2} = w + l$

Subtract both sides by either length or width depending on what variable you chose to make by itself (in this case I subtracted the length variable because I wanted the width variable by itself).
$\frac{p}{2} - l = w + l - l$
$l's$ $cancel$ $out$
p/2 - l = w

$a = l * w$

You replace w with the equation above p/2 - l = w
$a = l( \frac{p}{2} - l)$

Multiply out the L.
$a = \frac{p}{2}l - l^{2}$

Plug in all your numbers a = 110 and p = 42
$110 = \frac{42}{2}l - l^{2}$
$110 = 21l - l^{2$

Move everything to the left side so $l^{2}$ would be positive (makes the equation easier when $l^{2}$ is positive).
$l^{2} - 21l + 110 = 0$

Factor.
$(l -10)(l-11) = 0$

Make each parenthesis set equal to 0.
$l-11=0$ $l-10=0$

Add.
$l = 11$ $l = 10$

By doing this you solve for both the width and length so the answer is:
w = 11 L = 10

8 0

3 years ago